Можешь помочь решить уравнения 6x-19=-x-10?

Конечно, давай решим эти уравнения вместе! 1) $6x - 19 = -x - 10$ $6x + x = -10 + 19$ $7x = 9$ $x = \frac{9}{7}$ $x \approx 1,29$ 2) $2(3x + 5) - 3(4x - 1) = 11,8$ $6x + 10 - 12x + 3 = 11,8$ $-6x + 13 = 11,8$ $-6x = 11,8 - 13$ $-6x = -1,2$ $x = \frac{-1,2}{-6}$ $x = 0,2$ 3) $\frac{3}{2} \cdot (1\frac{1}{2}x + \frac{3}{5}) - \frac{4}{5} \cdot (\frac{5}{12}x - \frac{1}{2}) = 1\frac{3}{5}$ $\frac{3}{2} \cdot (\frac{3}{2}x + \frac{3}{5}) - \frac{4}{5} \cdot (\frac{5}{12}x - \frac{1}{2}) = \frac{8}{5}$ $\frac{9}{4}x + \frac{9}{10} - \frac{1}{3}x + \frac{2}{5} = \frac{8}{5}$ $(\frac{9}{4} - \frac{1}{3})x = \frac{8}{5} - \frac{9}{10} - \frac{2}{5}$ $(\frac{27}{12} - \frac{4}{12})x = \frac{16}{10} - \frac{9}{10} - \frac{4}{10}$ $\frac{23}{12}x = \frac{3}{10}$ $x = \frac{3}{10} \cdot \frac{12}{23}$ $x = \frac{18}{115}$ 4) $\frac{4}{x - 1,2} = \frac{15}{x - 10}$ $4(x - 10) = 15(x - 1,2)$ $4x - 40 = 15x - 18$ $4x - 15x = -18 + 40$ $-11x = 22$ $x = -2$ 5) $\frac{5}{6} = \frac{5x + 6}{2x + 3,2}$ $5(2x + 3,2) = 6(5x + 6)$ $10x + 16 = 30x + 36$ $10x - 30x = 36 - 16$ $-20x = 20$ $x = -1$ 6) $\frac{3x}{10} - \frac{7}{15} = \frac{x}{6}$ $\frac{9x}{30} - \frac{14}{30} = \frac{5x}{30}$ $9x - 14 = 5x$ $9x - 5x = 14$ $4x = 14$ $x = \frac{14}{4} = \frac{7}{2}$ $x = 3,5$ **Ответы:** 1) $x \approx 1,29$ 2) $x = 0,2$ 3) $x = \frac{18}{115}$ 4) $x = -2$ 5) $x = -1$ 6) $x = 3,5$