Представь в виде обыкновенной дроби число 1,(3)

- a) $1,(3) = 1 + 0,(3) = 1 + \frac{3}{9} = 1 + \frac{1}{3} = \frac{4}{3}$ - б) $2,(25) = 2 + 0,(25) = 2 + \frac{25}{99} = \frac{2 \cdot 99 + 25}{99} = \frac{198 + 25}{99} = \frac{223}{99}$ - в) $1,6(7) = 1,6 + 0,0(7) = \frac{16}{10} + \frac{7}{90} = \frac{16 \cdot 9 + 7}{90} = \frac{144 + 7}{90} = \frac{151}{90}$ - г) $0,41(6) = 0,41 + 0,00(6) = \frac{41}{100} + \frac{6}{900} = \frac{41 \cdot 9 + 6}{900} = \frac{369 + 6}{900} = \frac{375}{900} = \frac{5}{12}$ - д) $5,2(45) = 5,2 + 0,0(45) = \frac{52}{10} + \frac{45}{990} = \frac{52 \cdot 99 + 45}{990} = \frac{5148 + 45}{990} = \frac{5193}{990} = \frac{1731}{330} = \frac{577}{110}$ - e) $3,6(020) = 3,6 + 0,0(020) = \frac{36}{10} + \frac{20}{9990} = \frac{36 \cdot 999 + 20}{9990} = \frac{35964 + 20}{9990} = \frac{35984}{9990} = \frac{17992}{4995}$