Помоги мне разложить на множители многочлен в номере 1 под цифрой 1

Задание 1 1) $m^3n^2 + 2m^2n^3 - m^2n^2 = m^2n^2(m + 2n - 1)$ 2) $6c^3d - 12c^2d^3 + 18c^3d^2 = 6c^2d(c - 2d^2 + 3cd)$ 3) $4x^2(a - b) - (a - b)^2 = (a - b)(4x^2 - (a - b)) = (a - b)(4x^2 - a + b)$ 4) $2x(a - b) + y(b - a) = 2x(a - b) - y(a - b) = (a - b)(2x - y)$ Задание 2 1) $x - y + ax - ay = (x - y) + a(x - y) = (x - y)(1 + a)$ 2) $6a^2c - 3a^2 + 2ac^2 - ac = 3a(2ac - a) + c(2ac - a) = (2ac - a)(3a + c) = a(2c - 1)(3a + c)$ 3) $2x^3 - 8xy - x^2y + 4y^2 = 2x(x^2 - 4y) - y(x^2 - 4y) = (x^2 - 4y)(2x - y)$ Задание 3 $(x - 3)^2 + (x - 3)(x + 3) = 0$ $(x - 3)((x - 3) + (x + 3)) = 0$ $(x - 3)(x - 3 + x + 3) = 0$ $(x - 3)(2x) = 0$ $x - 3 = 0$ или $2x = 0$ $x = 3$ или $x = 0$ **Ответ: x = 3, x = 0** Задание 4 1) $(3 + x)(x - 3) = (x + 3)(x - 3) = x^2 - 9$ 2) $(0,5q + \frac{1}{3}p^2)(\frac{1}{3}p^2 - 0,5q) = (\frac{1}{3}p^2 + 0,5q)(\frac{1}{3}p^2 - 0,5q) = (\frac{1}{3}p^2)^2 - (0,5q)^2 = \frac{1}{9}p^4 - 0,25q^2$ Задание 5 1) $25n^2 - m^2 = (5n - m)(5n + m)$ 2) $16x^2y^2 - 9b^6 = (4xy - 3b^3)(4xy + 3b^3)$ 3) $(2a + b)^2 - (2b + a)^2 = ((2a + b) - (2b + a))((2a + b) + (2b + a)) = (2a + b - 2b - a)(2a + b + 2b + a) = (a - b)(3a + 3b) = 3(a - b)(a + b)$ Задание 6 1) $(\frac{1}{3}a^2b - b^2)^2 = (\frac{1}{3}a^2b)^2 - 2(\frac{1}{3}a^2b)(b^2) + (b^2)^2 = \frac{1}{9}a^4b^2 - \frac{2}{3}a^2b^3 + b^4$ 2) $(5a + 6b)^2 = (5a)^2 + 2(5a)(6b) + (6b)^2 = 25a^2 + 60ab + 36b^2$ Задание 7 1) $4b^2 - 24bc + 36c^2 = (2b)^2 - 2(2b)(6c) + (6c)^2 = (2b - 6c)^2 = 4(b - 3c)^2$ 2) $4m^2 + 20mn + 25n^2 = (2m)^2 + 2(2m)(5n) + (5n)^2 = (2m + 5n)^2$