Ты просишь выполнить действия с дробями: $3\frac{5}{6} + 5\frac{1}{7}$

Конечно, давай решим эти примеры с дробями! а) $3\frac{5}{6} + 5\frac{1}{7} = 3\frac{35}{42} + 5\frac{6}{42} = (3+5) + (\frac{35}{42} + \frac{6}{42}) = 8 + \frac{41}{42} = 8\frac{41}{42}$ б) $6\frac{5}{4} = 6 + \frac{5}{4} = 6 + \frac{4}{4} + \frac{1}{4} = 6 + 1 + \frac{1}{4} = 7\frac{1}{4}$ в) $7\frac{5}{8} - 5\frac{3}{6} = 7\frac{15}{24} - 5\frac{12}{24} = (7-5) + (\frac{15}{24} - \frac{12}{24}) = 2 + \frac{3}{24} = 2\frac{1}{8}$ г) $\frac{3}{10} - \frac{4}{15} = \frac{9}{30} - \frac{8}{30} = \frac{1}{30}$ д) $1\frac{2}{3} + \frac{5}{6} = 1\frac{4}{6} + \frac{5}{6} = 1 + \frac{4}{6} + \frac{5}{6} = 1 + \frac{9}{6} = 1 + \frac{6}{6} + \frac{3}{6} = 1 + 1 + \frac{1}{2} = 2\frac{1}{2}$ е) $5 - 3\frac{2}{7} = 4\frac{7}{7} - 3\frac{2}{7} = (4-3) + (\frac{7}{7} - \frac{2}{7}) = 1 + \frac{5}{7} = 1\frac{5}{7}$ ж) $4\frac{3}{9} = 4\frac{1}{3}$ з) $\frac{5}{8} : \frac{9}{10} = \frac{5}{8} * \frac{10}{9} = \frac{50}{72} = \frac{25}{36}$ и) $9\frac{1}{2} : 1\frac{1}{2} = \frac{19}{2} : \frac{3}{2} = \frac{19}{2} * \frac{2}{3} = \frac{19}{3} = 6\frac{1}{3}$ к) $2\frac{6}{7} : 1\frac{3}{7} = \frac{20}{7} : \frac{10}{7} = \frac{20}{7} * \frac{7}{10} = \frac{20}{10} = 2$ л) $6\frac{3}{5} * 10 = \frac{33}{5} * 10 = \frac{330}{5} = 66$ м) $3\frac{2}{6} : 1\frac{1}{3} = 3\frac{1}{3} : 1\frac{1}{3} = \frac{10}{3} : \frac{4}{3} = \frac{10}{3} * \frac{3}{4} = \frac{10}{4} = \frac{5}{2} = 2\frac{1}{2}