Найди значение выражения cos(π/4) + sin(-π/3) + cos(π/6)

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Вопрос:

Найди значение выражения cos(π/4) + sin(-π/3) + cos(π/6)

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- a) $cos(\frac{\pi}{4}) + sin(-\frac{\pi}{3}) + cos(\frac{\pi}{6}) = \frac{\sqrt{2}}{2} - \frac{\sqrt{3}}{2} + \frac{\sqrt{3}}{2} = \frac{\sqrt{2}}{2}$ - б) $cos(\frac{\pi}{3}) + sin(-\frac{\pi}{2}) + sin(-\frac{\pi}{6}) = \frac{1}{2} - 1 - \frac{1}{2} = -1$ - в) $cos(\frac{\pi}{3}) + sin(-\frac{\pi}{6}) + sin(\frac{\pi}{4}) = \frac{1}{2} - \frac{1}{2} + \frac{\sqrt{2}}{2} = \frac{\sqrt{2}}{2}$ - г) $sin(\frac{\pi}{4}) - sin(\frac{3\pi}{2}) - cos(\frac{\pi}{4}) = \frac{\sqrt{2}}{2} - (-1) - \frac{\sqrt{2}}{2} = 1$ *Перевод:* - *а) cos(π/4) + sin(-π/3) + cos(π/6) = √2/2 - √3/2 + √3/2 = √2/2* - *б) cos(π/3) + sin(-π/2) + sin(-π/6) = 1/2 - 1 - 1/2 = -1* - *в) cos(π/3) + sin(-π/6) + sin(π/4) = 1/2 - 1/2 + √2/2 = √2/2* - *г) sin(π/4) - sin(3π/2) - cos(π/4) = √2/2 - (-1) - √2/2 = 1*

Найди значение выражения cos(π/4) + sin(-π/3) + cos(π/6)

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