Выполни вычисления в заданиях про дроби и степени

- Задание 1. 1) $$(\frac{1}{12} - \frac{17}{15}) \cdot \frac{10}{3} = (\frac{5}{60} - \frac{68}{60}) \cdot \frac{10}{3} = -\frac{63}{60} \cdot \frac{10}{3} = -\frac{21}{20} \cdot \frac{10}{1} = -\frac{21}{2} = -10,5$$ 2) $$(\frac{7}{15} + \frac{19}{30}) \cdot \frac{9}{11} = (\frac{14}{30} + \frac{19}{30}) \cdot \frac{9}{11} = \frac{33}{30} \cdot \frac{9}{11} = \frac{11}{10} \cdot \frac{3}{11} = \frac{3}{10} = 0,3$$ 3) $$(\frac{3}{25} - \frac{2}{35}) \cdot 14 = (\frac{21}{175} - \frac{10}{175}) \cdot 14 = \frac{11}{175} \cdot 14 = \frac{11}{25} \cdot 2 = \frac{22}{25} = 0,88$$ 4) $$(\frac{1}{30} + \frac{7}{10}) \cdot 6 = (\frac{1}{30} + \frac{21}{30}) \cdot 6 = \frac{22}{30} \cdot 6 = \frac{11}{15} \cdot 6 = \frac{11}{5} \cdot 2 = \frac{22}{5} = 4,4$$ - Задание 2. 1) $$(2\frac{3}{17} + \frac{1}{34}) \cdot 17 = (2\frac{6}{34} + \frac{1}{34}) \cdot 17 = 2\frac{7}{34} \cdot 17 = \frac{75}{34} \cdot 17 = \frac{75}{2} = 37,5$$ 2) $$(1\frac{1}{4} - \frac{3}{19}) \cdot 19 = (\frac{5}{4} - \frac{3}{19}) \cdot 19 = (\frac{95}{76} - \frac{12}{76}) \cdot 19 = \frac{83}{76} \cdot 19 = \frac{83}{4} = 20,75$$ 3) $$4\frac{3}{8} : (3 + 1\frac{4}{13}) = \frac{35}{8} : (3 + \frac{17}{13}) = \frac{35}{8} : (\frac{39}{13} + \frac{17}{13}) = \frac{35}{8} : \frac{56}{13} = \frac{35}{8} \cdot \frac{13}{56} = \frac{5}{8} \cdot \frac{13}{8} = \frac{65}{64} = 1\frac{1}{64}$$ 4) $$5\frac{2}{5} : (3\frac{1}{4} - 2\frac{4}{5}) = \frac{27}{5} : (\frac{13}{4} - \frac{14}{5}) = \frac{27}{5} : (\frac{65}{20} - \frac{56}{20}) = \frac{27}{5} : \frac{9}{20} = \frac{27}{5} \cdot \frac{20}{9} = 3 \cdot 4 = 12$$ - Задание 3. 1) $$\frac{3,6}{5,9 - 1,1} = \frac{3,6}{4,8} = \frac{36}{48} = \frac{3}{4} = 0,75$$ 2) $$\frac{1,3 + 9,2}{1,5} = \frac{10,5}{1,5} = \frac{105}{15} = 7$$ 3) $$\frac{28}{17,5 \cdot 0,5} = \frac{28}{8,75} = \frac{2800}{875} = \frac{112}{35} = \frac{16}{5} = 3,2$$ 4) $$\frac{5,6 - 0,7}{0,8} = \frac{4,9}{0,8} = \frac{49}{8} = 6,125$$