Помоги решить примеры по математике с дробями из 1, 2 и 3 вариантов

Привет! Давай решим примеры из твоего варианта по порядку. Вариант 1: 1. $\frac{7}{10} + \frac{1}{10} = \frac{7+1}{10} = \frac{8}{10} = \frac{4}{5}$ 2. $2\frac{3}{5} + 14\frac{1}{5} = (2 + 14) + (\frac{3}{5} + \frac{1}{5}) = 16 + \frac{4}{5} = 16\frac{4}{5}$ 3. $\frac{18}{19} - \frac{5}{19} = \frac{18-5}{19} = \frac{13}{19}$ 4. $3\frac{2}{7} - 2\frac{6}{7} = 3\frac{2}{7} - 2\frac{6}{7} = 2\frac{9}{7} - 2\frac{6}{7} = \frac{3}{7}$ 5. $\frac{9}{16} : 3 = \frac{9}{16} \cdot \frac{1}{3} = \frac{9}{48} = \frac{3}{16}$ 6. $\frac{5}{8} + \frac{3}{4} = \frac{5}{8} + \frac{6}{8} = \frac{11}{8} = 1\frac{3}{8}$ 7. $\frac{5}{8} \cdot 2 = \frac{5}{8} \cdot \frac{2}{1} = \frac{10}{8} = \frac{5}{4} = 1\frac{1}{4}$ 8. $\frac{17}{20} : 7 = \frac{17}{20} \cdot \frac{1}{7} = \frac{17}{140}$ Вариант 2: 1. $\frac{15}{28} - \frac{5}{28} = \frac{15-5}{28} = \frac{10}{28} = \frac{5}{14}$ 2. $7\frac{8}{9} - 6\frac{2}{9} = (7 - 6) + (\frac{8}{9} - \frac{2}{9}) = 1 + \frac{6}{9} = 1\frac{2}{3}$ 3. $\frac{3}{4} + \frac{1}{2} = \frac{3}{4} + \frac{2}{4} = \frac{5}{4} = 1\frac{1}{4}$ 4. $\frac{6}{35} \cdot 3 = \frac{6 \cdot 3}{35} = \frac{18}{35}$ 5. $5\frac{8}{13} + 2\frac{5}{13} = (5 + 2) + (\frac{8}{13} + \frac{5}{13}) = 7 + \frac{13}{13} = 7 + 1 = 8$ 6. $\frac{3}{4} : 2 = \frac{3}{4} \cdot \frac{1}{2} = \frac{3}{8}$ 7. $\frac{10}{27} : \frac{5}{7} = \frac{10}{27} \cdot \frac{7}{5} = \frac{2}{27} \cdot \frac{7}{1} = \frac{14}{27}$ Вариант 3: 1. $\frac{8}{25} + \frac{7}{25} = \frac{8+7}{25} = \frac{15}{25} = \frac{3}{5}$ 2. $\frac{8}{9} - \frac{2}{9} = \frac{8-2}{9} = \frac{6}{9} = \frac{2}{3}$ 3. $3\frac{5}{6} - 1\frac{1}{6} = (3 - 1) + (\frac{5}{6} - \frac{1}{6}) = 2 + \frac{4}{6} = 2\frac{2}{3}$ 4. $\frac{3}{9} : 3 = \frac{1}{3} \cdot \frac{1}{3} = \frac{1}{9}$ 5. $7\frac{4}{21} + 6\frac{20}{21} = (7 + 6) + (\frac{4}{21} + \frac{20}{21}) = 13 + \frac{24}{21} = 13 + 1\frac{3}{21} = 14\frac{1}{7}$ 6. $\frac{5}{9} \cdot 3 = \frac{5}{3} \cdot 1 = \frac{5}{3} = 1\frac{2}{3}$ 7. $5\frac{5}{7} - 4\frac{5}{7} = (5 - 4) + (\frac{5}{7} - \frac{5}{7}) = 1 + 0 = 1$ 8. $\frac{10}{63} : 2 = \frac{10}{63} \cdot \frac{1}{2} = \frac{5}{63}$ Надеюсь, теперь тебе стало понятнее, как решать такие примеры!