Выполни действия в упражнении 17

- a) $5\frac{6}{7} + 1\frac{4}{5} = 5 + \frac{6}{7} + 1 + \frac{4}{5} = 6 + \frac{6 \cdot 5 + 4 \cdot 7}{7 \cdot 5} = 6 + \frac{30 + 28}{35} = 6 + \frac{58}{35} = 6 + 1\frac{23}{35} = 7\frac{23}{35}$ *Перевод:* - a) $5\frac{6}{7} + 1\frac{4}{5} = 5 + \frac{6}{7} + 1 + \frac{4}{5} = 6 + \frac{6 \cdot 5 + 4 \cdot 7}{7 \cdot 5} = 6 + \frac{30 + 28}{35} = 6 + \frac{58}{35} = 6 + 1\frac{23}{35} = 7\frac{23}{35}$ - б) $7\frac{8}{9} - 6\frac{1}{6} = 7 + \frac{8}{9} - 6 - \frac{1}{6} = 1 + \frac{8 \cdot 2 - 1 \cdot 3}{18} = 1 + \frac{16-3}{18} = 1 + \frac{13}{18} = 1\frac{13}{18}$ *Перевод:* - б) $7\frac{8}{9} - 6\frac{1}{6} = 7 + \frac{8}{9} - 6 - \frac{1}{6} = 1 + \frac{8 \cdot 2 - 1 \cdot 3}{18} = 1 + \frac{16-3}{18} = 1 + \frac{13}{18} = 1\frac{13}{18}$ - в) $3\frac{4}{15} - 2\frac{5}{7} = 3 + \frac{4}{15} - 2 - \frac{5}{7} = 1 + \frac{4 \cdot 7 - 5 \cdot 15}{15 \cdot 7} = 1 + \frac{28 - 75}{105} = 1 - \frac{47}{105} = \frac{105 - 47}{105} = \frac{58}{105}$ *Перевод:* - в) $3\frac{4}{15} - 2\frac{5}{7} = 3 + \frac{4}{15} - 2 - \frac{5}{7} = 1 + \frac{4 \cdot 7 - 5 \cdot 15}{15 \cdot 7} = 1 + \frac{28 - 75}{105} = 1 - \frac{47}{105} = \frac{105 - 47}{105} = \frac{58}{105}$ - г) $5\frac{3}{10} - 3\frac{1}{5} = 5 + \frac{3}{10} - 3 - \frac{1}{5} = 2 + \frac{3 - 2}{10} = 2 + \frac{1}{10} = 2\frac{1}{10}$ *Перевод:* - г) $5\frac{3}{10} - 3\frac{1}{5} = 5 + \frac{3}{10} - 3 - \frac{1}{5} = 2 + \frac{3 - 2}{10} = 2 + \frac{1}{10} = 2\frac{1}{10}$ - д) $4\frac{9}{10} : 3\frac{8}{9} = \frac{49}{10} : \frac{35}{9} = \frac{49}{10} \cdot \frac{9}{35} = \frac{7}{10} \cdot \frac{9}{5} = \frac{63}{50} = 1\frac{13}{50}$ *Перевод:* - д) $4\frac{9}{10} : 3\frac{8}{9} = \frac{49}{10} : \frac{35}{9} = \frac{49}{10} \cdot \frac{9}{35} = \frac{7}{10} \cdot \frac{9}{5} = \frac{63}{50} = 1\frac{13}{50}$ - e) $8\frac{5}{6} : 7\frac{1}{3} = \frac{53}{6} : \frac{22}{3} = \frac{53}{6} \cdot \frac{3}{22} = \frac{53}{2} \cdot \frac{1}{22} = \frac{53}{44} = 1\frac{9}{44}$ *Перевод:* - e) $8\frac{5}{6} : 7\frac{1}{3} = \frac{53}{6} : \frac{22}{3} = \frac{53}{6} \cdot \frac{3}{22} = \frac{53}{2} \cdot \frac{1}{22} = \frac{53}{44} = 1\frac{9}{44}$ - ж) $6\frac{2}{7} : 1\frac{3}{10} = \frac{44}{7} : \frac{13}{10} = \frac{44}{7} \cdot \frac{10}{13} = \frac{440}{91} = 4\frac{76}{91}$ *Перевод:* - ж) $6\frac{2}{7} : 1\frac{3}{10} = \frac{44}{7} : \frac{13}{10} = \frac{44}{7} \cdot \frac{10}{13} = \frac{440}{91} = 4\frac{76}{91}$ - з) $3\frac{6}{5} : 2\frac{7}{13} = \frac{21}{5} : \frac{33}{13} = \frac{21}{5} \cdot \frac{13}{33} = \frac{7}{5} \cdot \frac{13}{11} = \frac{91}{55} = 1\frac{36}{55}$ *Перевод:* - з) $3\frac{6}{5} : 2\frac{7}{13} = \frac{21}{5} : \frac{33}{13} = \frac{21}{5} \cdot \frac{13}{33} = \frac{7}{5} \cdot \frac{13}{11} = \frac{91}{55} = 1\frac{36}{55}