Помоги решить примеры с дробями из упражнения под номером 1a

1. a) $\frac{3}{7} * \frac{5}{11} = \frac{3*5}{7*11} = \frac{15}{77}$ б) $3\frac{3}{5} * 1\frac{1}{9} = \frac{3*5+3}{5} * \frac{1*9+1}{9} = \frac{18}{5} * \frac{10}{9} = \frac{18*10}{5*9} = \frac{2*2}{1*1} = 4$ в) $\frac{5}{9} : \frac{10}{27} = \frac{5}{9} * \frac{27}{10} = \frac{5*27}{9*10} = \frac{1*3}{1*2} = \frac{3}{2} = 1\frac{1}{2}$ г) $\frac{12}{13} : 6 = \frac{12}{13} : \frac{6}{1} = \frac{12}{13} * \frac{1}{6} = \frac{12*1}{13*6} = \frac{2*1}{13*1} = \frac{2}{13}$ 2. $4,292 : (9-5,3) + 2,6 * (1,89) = 4,292 : 3,7 + 2,6 * 1,89 = 1,16 + 4,914 = 6,074$ 3. a) $5\frac{1}{3} : \frac{2}{3} - 1\frac{5}{18} * 6 = \frac{16}{3} : \frac{2}{3} - \frac{23}{18} * 6 = \frac{16}{3} * \frac{3}{2} - \frac{23}{18} * 6 = \frac{16*3}{3*2} - \frac{23*6}{18*1} = \frac{8*1}{1*1} - \frac{23*1}{3*1} = 8 - \frac{23}{3} = \frac{8*3 - 23}{3} = \frac{24-23}{3} = \frac{1}{3}$ б) $(1\frac{3}{5} + 2\frac{1}{5}) : 1\frac{9}{10} + (1\frac{7}{10} - \frac{4}{5}) : \frac{3}{7} = (\frac{8}{5} + \frac{11}{5}) : \frac{19}{10} + (\frac{17}{10} - \frac{8}{10}) : \frac{3}{7} = \frac{19}{5} : \frac{19}{10} + \frac{9}{10} : \frac{3}{7} = \frac{19}{5} * \frac{10}{19} + \frac{9}{10} * \frac{7}{3} = \frac{19*10}{5*19} + \frac{9*7}{10*3} = \frac{1*2}{1*1} + \frac{3*7}{10*1} = 2 + \frac{21}{10} = \frac{2*10+21}{10} = \frac{41}{10} = 4\frac{1}{10}$