Найди значение выражения: 7 1/3 + 5 3/5

a) $7\frac{1}{3} + 5\frac{3}{5} = 7 + \frac{1}{3} + 5 + \frac{3}{5} = (7+5) + (\frac{1}{3} + \frac{3}{5}) = 12 + (\frac{5}{15} + \frac{9}{15}) = 12 + \frac{14}{15} = 12\frac{14}{15}$ б) $6\frac{2}{3} - 1\frac{2}{5} = 6 + \frac{2}{3} - (1 + \frac{2}{5}) = 6 + \frac{2}{3} - 1 - \frac{2}{5} = (6-1) + (\frac{2}{3} - \frac{2}{5}) = 5 + (\frac{10}{15} - \frac{6}{15}) = 5 + \frac{4}{15} = 5\frac{4}{15}$ в) $3\frac{3}{4} + 4\frac{7}{9} = 3 + \frac{3}{4} + 4 + \frac{7}{9} = (3+4) + (\frac{3}{4} + \frac{7}{9}) = 7 + (\frac{27}{36} + \frac{28}{36}) = 7 + \frac{55}{36} = 7 + 1\frac{19}{36} = 8\frac{19}{36}$ г) $20\frac{5}{6} - 2\frac{3}{4} = 20 + \frac{5}{6} - (2 + \frac{3}{4}) = 20 + \frac{5}{6} - 2 - \frac{3}{4} = (20-2) + (\frac{5}{6} - \frac{3}{4}) = 18 + (\frac{10}{12} - \frac{9}{12}) = 18 + \frac{1}{12} = 18\frac{1}{12}$ д) $39\frac{5}{9} - 4\frac{1}{6} = 39 + \frac{5}{9} - (4 + \frac{1}{6}) = 39 + \frac{5}{9} - 4 - \frac{1}{6} = (39-4) + (\frac{5}{9} - \frac{1}{6}) = 35 + (\frac{10}{18} - \frac{3}{18}) = 35 + \frac{7}{18} = 35\frac{7}{18}$ е) $11\frac{5}{8} + 8\frac{5}{6} = 11 + \frac{5}{8} + 8 + \frac{5}{6} = (11+8) + (\frac{5}{8} + \frac{5}{6}) = 19 + (\frac{15}{24} + \frac{20}{24}) = 19 + \frac{35}{24} = 19 + 1\frac{11}{24} = 20\frac{11}{24}$ ж) $(\frac{2}{7} + 3\frac{1}{4}) - (\frac{11}{14} + \frac{13}{28}) = (\frac{2}{7} + 3 + \frac{1}{4}) - (\frac{11}{14} + \frac{13}{28}) = (3 + \frac{2}{7} + \frac{1}{4}) - (\frac{22}{28} + \frac{13}{28}) = (3 + \frac{8}{28} + \frac{7}{28}) - \frac{35}{28} = 3 + \frac{15}{28} - \frac{35}{28} = 3 - \frac{20}{28} = 3 - \frac{5}{7} = 2\frac{7}{7} - \frac{5}{7} = 2\frac{2}{7}$ з) $(8\frac{7}{12} - 2\frac{5}{8}) - (3\frac{7}{12} - 1\frac{1}{3}) = (8 + \frac{7}{12} - (2 + \frac{5}{8})) - (3 + \frac{7}{12} - (1 + \frac{1}{3})) = (8 + \frac{7}{12} - 2 - \frac{5}{8}) - (3 + \frac{7}{12} - 1 - \frac{1}{3}) = (8-2) + (\frac{7}{12} - \frac{5}{8}) - ((3-1) + (\frac{7}{12} - \frac{1}{3})) = 6 + (\frac{14}{24} - \frac{15}{24}) - (2 + (\frac{7}{12} - \frac{4}{12})) = 6 - \frac{1}{24} - (2 + \frac{3}{12}) = 6 - \frac{1}{24} - 2 - \frac{1}{4} = (6-2) - (\frac{1}{24} + \frac{1}{4}) = 4 - (\frac{1}{24} + \frac{6}{24}) = 4 - \frac{7}{24} = 3\frac{24}{24} - \frac{7}{24} = 3\frac{17}{24}$