Вычисли значение выражения: 1/5 - 41/50

Конечно, давай помогу! **Задание 1** 1) $\frac{1}{5} - \frac{41}{50} = \frac{10}{50} - \frac{41}{50} = -\frac{31}{50}$ 2) $\frac{1}{5} + \frac{53}{50} = \frac{10}{50} + \frac{53}{50} = \frac{63}{50} = 1\frac{13}{50}$ 5) $\frac{1}{2} - \frac{9}{10} = \frac{5}{10} - \frac{9}{10} = -\frac{4}{10} = -\frac{2}{5}$ 6) $\frac{1}{2} + \frac{11}{10} = \frac{5}{10} + \frac{11}{10} = \frac{16}{10} = \frac{8}{5} = 1\frac{3}{5}$ 9) $\frac{1}{10} - \frac{39}{50} = \frac{5}{50} - \frac{39}{50} = -\frac{34}{50} = -\frac{17}{25}$ 10) $\frac{1}{2} + \frac{31}{20} = \frac{10}{20} + \frac{31}{20} = \frac{41}{20} = 2\frac{1}{20}$ **Задание 2** 1) $\frac{21}{5} \cdot \frac{3}{7} = \frac{21 \cdot 3}{5 \cdot 7} = \frac{3 \cdot 3}{5 \cdot 1} = \frac{9}{5} = 1\frac{4}{5}$ 2) $\frac{14}{5} : \frac{7}{2} = \frac{14}{5} \cdot \frac{2}{7} = \frac{14 \cdot 2}{5 \cdot 7} = \frac{2 \cdot 2}{5 \cdot 1} = \frac{4}{5}$ 5) $\frac{5}{3} \cdot \frac{9}{2} = \frac{5 \cdot 9}{3 \cdot 2} = \frac{5 \cdot 3}{1 \cdot 2} = \frac{15}{2} = 7\frac{1}{2}$ 6) $\frac{21}{2} : \frac{3}{5} = \frac{21}{2} \cdot \frac{5}{3} = \frac{21 \cdot 5}{2 \cdot 3} = \frac{7 \cdot 5}{2 \cdot 1} = \frac{35}{2} = 17\frac{1}{2}$ 9) $\frac{3}{4} \cdot \frac{6}{5} = \frac{3 \cdot 6}{4 \cdot 5} = \frac{3 \cdot 3}{2 \cdot 5} = \frac{9}{10}$ 10) $\frac{15}{4} : \frac{3}{7} = \frac{15}{4} \cdot \frac{7}{3} = \frac{15 \cdot 7}{4 \cdot 3} = \frac{5 \cdot 7}{4 \cdot 1} = \frac{35}{4} = 8\frac{3}{4}$ **Задание 3** 1) $6,9 + 7,4 = 14,3$ 2) $3,9 - 7,3 = -3,4$ 5) $8,3 + 5,4 = 13,7$ 6) $4,4 - 1,7 = 2,7$ 9) $9,8 + 8,6 = 18,4$ 10) $6,4 - 4,8 = 1,6$