1) √0,25; 2) √5(32); 3) √3(-3 3/8);

1) $\sqrt{0.25} = 0.5$ 2) $\sqrt[5]{32} = \sqrt[5]{2^5} = 2$ 3) $\sqrt[3]{-3 \frac{3}{8}} = \sqrt[3]{-\frac{27}{8}} = -\frac{3}{2} = -1.5$