1) $\sqrt{0,49}; 2) \sqrt[3]{64}; 3) \sqrt[3]{-2 \frac{10}{27}} ; ...

1) $\sqrt{0,49} = 0,7$ 2) $\sqrt[3]{64} = 4$ 3) $\sqrt[3]{-2 \frac{10}{27}} = \sqrt[3]{-\frac{64}{27}} = -\frac{4}{3} = -1 \frac{1}{3}$ 4) $0,5 \cdot \sqrt[4]{81} = 0,5 \cdot 3 = 1,5$ 5) $\sqrt[4]{\frac{81}{16}} + \sqrt[3]{-\frac{1}{27}} = \frac{3}{2} - \frac{1}{3} = 1,5 - 0,333... = \frac{9-2}{6} = \frac{7}{6} = 1 \frac{1}{6}$ 6) $(2\sqrt[3]{6})^3 = 2^3 \cdot (\sqrt[3]{6})^3 = 8 \cdot 6 = 48$ 7) $\frac{6}{(3\sqrt{2})^2} = \frac{6}{9 \cdot 2} = \frac{6}{18} = \frac{1}{3}$ 8) $-3 \cdot \sqrt[3]{(-6)^3} = -3 \cdot (-6) = 18$ 9) $\sqrt[4]{81} \cdot \sqrt[3]{8} = 3 \cdot 2 = 6$ 10) $\sqrt[4]{1} \cdot \sqrt[3]{-0,125} = 1 \cdot (-0,5) = -0,5$ 11) $\sqrt[5]{27} \cdot \sqrt[5]{9} = \sqrt[5]{27 \cdot 9} = \sqrt[5]{243} = 3$ 12) $\sqrt[4]{9} \cdot \sqrt[4]{18} \cdot \sqrt[4]{8} = \sqrt[4]{9 \cdot 18 \cdot 8} = \sqrt[4]{1296} = \sqrt[4]{6^4} = 6$ 13) $\frac{\sqrt[3]{500}}{5\sqrt[3]{4}} = \frac{1}{5} \cdot \sqrt[3]{\frac{500}{4}} = \frac{1}{5} \cdot \sqrt[3]{125} = \frac{1}{5} \cdot 5 = 1$ 14) $(3^{\frac{21}{4}} : 3^{\frac{5}{4}})^{\frac{1}{2}} = (3^{\frac{21}{4} - \frac{5}{4}})^{\frac{1}{2}} = (3^{\frac{16}{4}})^{\frac{1}{2}} = (3^4)^{\frac{1}{2}} = 3^2 = 9$