2. Найдите значение выражения: А) (-0.2+1/3):(-3.2); Б) (-0.5-(-3/4)):(-0.2); В) (-0.3-1/5):(-1/6); Г) -3 7/20+(-0.25:(-1/4)-1.5:(-3/16)):(-4 1/11); Д) (1/3+1/2)*0.6+0.6:(3/5); Е) (6 8/25:(-1)-(-0.8)*(-0.1)):(0.25:1.25-1 3/5:(-5 1/3)); Ё) -5:(-1/5-3/4):(-1.9)+1/6:(-2); Ж) (-0.864:1.2-0.2*(-3.5*9/11-9/11*7.5)+0.92):(-4/7);

Привет! Давай решим примеры по порядку. а) $(-0.2 + \frac{1}{3}) : (-3.2) = (-\frac{1}{5} + \frac{1}{3}) : (-3.2) = (\frac{-3 + 5}{15}) : (-3.2) = \frac{2}{15} : (-\frac{32}{10}) = \frac{2}{15} \cdot (-\frac{10}{32}) = -\frac{20}{480} = -\frac{1}{24}$ б) $(-0.5 - (-\frac{3}{4})) : (-0.2) = (-0.5 + 0.75) : (-0.2) = 0.25 : (-0.2) = \frac{0.25}{-0.2} = -\frac{25}{20} = -1.25$ в) $(-0.3 - \frac{1}{5}) : (-\frac{1}{6}) = (-0.3 - 0.2) : (-\frac{1}{6}) = -0.5 : (-\frac{1}{6}) = -\frac{1}{2} \cdot (-6) = 3$ г) $-3\frac{7}{20} + ((-0.25 : (-\frac{1}{4}) - 1.5 : (-\frac{3}{16})) : (-4\frac{1}{11})) = -3.35 + ((1 - 1.5 \cdot (-\frac{16}{3})) : (-\frac{45}{11})) = -3.35 + ((1 + 8) : (-\frac{45}{11})) = -3.35 + (9 : (-\frac{45}{11})) = -3.35 + (9 \cdot (-\frac{11}{45})) = -3.35 - \frac{11}{5} = -3.35 - 2.2 = -5.55$ д) $(\frac{1}{3} + \frac{1}{2}) \cdot 0.6 + 0.6 : \frac{3}{5} = (\frac{2+3}{6}) \cdot 0.6 + 0.6 : 0.6 = \frac{5}{6} \cdot 0.6 + 1 = 0.5 + 1 = 1.5$ е) $(6\frac{8}{25} : (-1) - (-0.8) \cdot (-0.1)) : (0.25 : 1.25 - 1\frac{3}{5} : (-5\frac{1}{3})) = (-6.32 - 0.08) : (0.2 - 1.6 : (-\frac{16}{3})) = -6.4 : (0.2 - 1.6 \cdot (-\frac{3}{16})) = -6.4 : (0.2 + 0.3) = -6.4 : 0.5 = -12.8$ ё) $-5 : (-\frac{1}{5} - \frac{3}{4}) : (-1.9) + \frac{1}{6} : (-2) = -5 : (-\frac{4+15}{20}) : (-1.9) - \frac{1}{12} = -5 : (-\frac{19}{20}) : (-1.9) - \frac{1}{12} = -5 \cdot (-\frac{20}{19}) : (-1.9) - \frac{1}{12} = (\frac{100}{19}) : (-\frac{19}{10}) - \frac{1}{12} = \frac{100}{19} \cdot (-\frac{10}{19}) - \frac{1}{12} = -\frac{1000}{361} - \frac{1}{12} \approx -2.77 - 0.08 = -2.85$ ж) $(-0.864 : 1.2 - 0.2 \cdot (-3.5 \cdot \frac{9}{11} - \frac{9}{11} \cdot 7.5) + 0.92) : (-\frac{4}{7}) = (-0.72 - 0.2 \cdot (-\frac{9}{11} \cdot (3.5 + 7.5)) + 0.92) : (-\frac{4}{7}) = (-0.72 - 0.2 \cdot (-\frac{9}{11} \cdot 11) + 0.92) : (-\frac{4}{7}) = (-0.72 - 0.2 \cdot (-9) + 0.92) : (-\frac{4}{7}) = (-0.72 + 1.8 + 0.92) : (-\frac{4}{7}) = 2 : (-\frac{4}{7}) = 2 \cdot (-\frac{7}{4}) = -3.5$