(12 21/32 + x) - 4 5/8 = 13 1/16

Привет! Давай решим эти уравнения по порядку. д) $(12 \frac{21}{32} + x) - 4 \frac{5}{8} = 13 \frac{1}{16}$ $12 \frac{21}{32} + x = 13 \frac{1}{16} + 4 \frac{5}{8}$ $12 \frac{21}{32} + x = 13 \frac{2}{32} + 4 \frac{20}{32}$ $12 \frac{21}{32} + x = 17 \frac{22}{32}$ $x = 17 \frac{22}{32} - 12 \frac{21}{32}$ $x = 5 \frac{1}{32}$ з) $100 - (x + 99 \frac{2}{5}) = \frac{3}{10}$ $x + 99 \frac{2}{5} = 100 - \frac{3}{10}$ $x + 99 \frac{2}{5} = 99 \frac{7}{10}$ $x = 99 \frac{7}{10} - 99 \frac{4}{10}$ $x = \frac{3}{10}$ е) $\frac{3}{4} + (10 \frac{27}{40} + a) = 15 \frac{3}{40}$ $10 \frac{27}{40} + a = 15 \frac{3}{40} - \frac{3}{4}$ $10 \frac{27}{40} + a = 15 \frac{3}{40} - \frac{30}{40}$ $10 \frac{27}{40} + a = 14 \frac{43}{40} - \frac{30}{40}$ $10 \frac{27}{40} + a = 14 \frac{13}{40}$ $a = 14 \frac{13}{40} - 10 \frac{27}{40}$ $a = 13 \frac{53}{40} - 10 \frac{27}{40}$ $a = 3 \frac{26}{40} = 3 \frac{13}{20}$ и) $\frac{8}{17} + (x + 1 \frac{1}{34}) = 5 \frac{1}{2}$ $x + 1 \frac{1}{34} = 5 \frac{17}{34} - \frac{16}{34}$ $x + 1 \frac{1}{34} = 5 \frac{1}{34}$ $x = 5 \frac{1}{34} - 1 \frac{1}{34}$ $x = 4$ ж) $(x - 4 \frac{5}{7}) + \frac{9}{14} = 1$ $x - 4 \frac{5}{7} = 1 - \frac{9}{14}$ $x - 4 \frac{5}{7} = \frac{5}{14}$ $x = \frac{5}{14} + 4 \frac{10}{14}$ $x = 4 \frac{15}{14} = 5 \frac{1}{14}$ к) $(\frac{12}{25} + x) + \frac{13}{50} = 2 \frac{17}{50}$ $\frac{24}{50} + x + \frac{13}{50} = 2 \frac{17}{50}$ $x + \frac{37}{50} = 2 \frac{17}{50}$ $x = 2 \frac{17}{50} - \frac{37}{50}$ $x = 1 \frac{67}{50} - \frac{37}{50}$ $x = 1 \frac{30}{50} = 1 \frac{3}{5}$