Разложите на множители.

Для решения этих задач воспользуемся формулой разности квадратов: $a^2 - b^2 = (a - b)(a + b)$. 1) $b^2 - d^2 = (b - d)(b + d)$ 2) $y^2 - x^2 = (y - x)(y + x)$ 3) $a^2 - 16 = a^2 - 4^2 = (a - 4)(a + 4)$ 4) $h^2 - 25 = h^2 - 5^2 = (h - 5)(h + 5)$ 5) $c^2 - 100 = c^2 - 10^2 = (c - 10)(c + 10)$ 6) $a^2 - 324 = a^2 - 18^2 = (a - 18)(a + 18)$ 7) $4m^2 - 121 = (2m)^2 - 11^2 = (2m - 11)(2m + 11)$ 8) $196 - 121a^2 = 14^2 - (11a)^2 = (14 - 11a)(14 + 11a)$ 9) $25a^2 - 16x^2 = (5a)^2 - (4x)^2 = (5a - 4x)(5a + 4x)$ 10) $169k^2 - 289l^2 = (13k)^2 - (17l)^2 = (13k - 17l)(13k + 17l)$ 11) $625b^2 - 36c^2 = (25b)^2 - (6c)^2 = (25b - 6c)(25b + 6c)$ 12) $484n^2 - 49c^2 = (22n)^2 - (7c)^2 = (22n - 7c)(22n + 7c)$ 13) $9n^2 - 144b^2 = (3n)^2 - (12b)^2 = (3n - 12b)(3n + 12b) = 3(n - 4b) \cdot 3(n + 4b) = 9(n - 4b)(n + 4b)$ 14) $256d^2 - 64z^2 = (16d)^2 - (8z)^2 = (16d - 8z)(16d + 8z) = 8(2d - z) \cdot 8(2d + z) = 64(2d - z)(2d + z)$ 15) $225x^2 - 900y^2 = (15x)^2 - (30y)^2 = (15x - 30y)(15x + 30y) = 15(x - 2y) \cdot 15(x + 2y) = 225(x - 2y)(x + 2y)$ 16) $a^4 - b^2 = (a^2)^2 - b^2 = (a^2 - b)(a^2 + b)$ 17) $49c^2y - 16d^4$. (В условии, вероятно, опечатка, так как $49c^2y$ не полный квадрат. Если $49c^2y^2 - 16d^4$, то: $(7cy)^2 - (4d^2)^2 = (7cy - 4d^2)(7cy + 4d^2)$) 18) $100e^4 - 81f^4g^2 = (10e^2)^2 - (9f^2g)^2 = (10e^2 - 9f^2g)(10e^2 + 9f^2g)$ 19) $144m^6 - 64n^4 = (12m^3)^2 - (8n^2)^2 = (12m^3 - 8n^2)(12m^3 + 8n^2) = 4(3m^3 - 2n^2) \cdot 4(3m^3 + 2n^2) = 16(3m^3 - 2n^2)(3m^3 + 2n^2)$ 20) $1024x^8 - 256y^8 = (32x^4)^2 - (16y^4)^2 = (32x^4 - 16y^4)(32x^4 + 16y^4) = 16(2x^4 - y^4) \cdot 16(2x^4 + y^4) = 256(2x^4 - y^4)(2x^4 + y^4)$