Выполните сложение дробей: 10/64 + 1/8, 7/3 + 14/27, 4/15 + 3/20 и другие.

1. $\frac{10}{64} + \frac{1}{8} = \frac{10}{64} + \frac{8}{64} = \frac{18}{64} = \frac{9}{32}$ 2. $\frac{7}{3} + \frac{14}{27} = \frac{63}{27} + \frac{14}{27} = \frac{77}{27} = 2\frac{23}{27}$ 3. $\frac{4}{15} + \frac{3}{20} = \frac{16}{60} + \frac{9}{60} = \frac{25}{60} = \frac{5}{12}$ 4. $\frac{5}{12} + \frac{17}{18} = \frac{15}{36} + \frac{34}{36} = \frac{49}{36} = 1\frac{13}{36}$ 5. $\frac{8}{10} + \frac{1}{100} = \frac{80}{100} + \frac{1}{100} = \frac{81}{100} = 0,81$ 6. $\frac{8}{11} + \frac{1}{10} = \frac{80}{110} + \frac{11}{110} = \frac{91}{110}$ 7. $\frac{5}{12} + \frac{7}{18} = \frac{15}{36} + \frac{14}{36} = \frac{29}{36}$ 8. $\frac{37}{115} + \frac{38}{175} = \frac{37}{5 \cdot 23} + \frac{38}{5 \cdot 35} = \frac{37 \cdot 35 + 38 \cdot 23}{5 \cdot 23 \cdot 35} = \frac{1295 + 874}{4025} = \frac{2169}{4025}$ 9. $\frac{9}{65} + \frac{16}{117} = \frac{9}{5 \cdot 13} + \frac{16}{9 \cdot 13} = \frac{9 \cdot 9 + 16 \cdot 5}{5 \cdot 9 \cdot 13} = \frac{81 + 80}{585} = \frac{161}{585}$ 10. $\frac{11}{100} + \frac{1}{5} = \frac{11}{100} + \frac{20}{100} = \frac{31}{100} = 0,31$ 11. $\frac{112}{4} + \frac{10}{100} = 28 + \frac{1}{10} = 28,1$ 12. $\frac{1}{70} + \frac{4}{210} = \frac{3}{210} + \frac{4}{210} = \frac{7}{210} = \frac{1}{30}$ 13. $\frac{30}{15} + \frac{11}{20} = 2 + \frac{11}{20} = 2\frac{11}{20} = 2,55$ 14. $\frac{14}{30} + \frac{18}{150} = \frac{70}{150} + \frac{18}{150} = \frac{88}{150} = \frac{44}{75}$ 15. $\frac{11}{66} + \frac{3}{77} = \frac{1}{6} + \frac{3}{77} = \frac{77 + 18}{462} = \frac{95}{462}$ 16. $\frac{3}{75} + \frac{71}{450} = \frac{1}{25} + \frac{71}{450} = \frac{18}{450} + \frac{71}{450} = \frac{89}{450}$ 17. $\frac{131}{120} + \frac{131}{180} = \frac{393}{360} + \frac{262}{360} = \frac{655}{360} = \frac{131}{72} = 1\frac{59}{72}$ 18. $\frac{12}{297} + \frac{104}{363} = \frac{4}{99} + \frac{104}{363} = \frac{4}{9 \cdot 11} + \frac{104}{3 \cdot 11 \cdot 11} = \frac{4 \cdot 11 \cdot 3 + 104 \cdot 9}{9 \cdot 11 \cdot 11} \text{ (упр.) } = \frac{4}{99} + \frac{104}{363} = \frac{44}{1089} + \frac{312}{1089} = \frac{356}{1089}$