Вычислите значения выражений с обыкновенными дробями.

1) $\frac{61}{64} - (\frac{7}{12} - \frac{5}{14}) \cdot (\frac{13}{16} + \frac{1}{2}) = \frac{61}{64} - (\frac{49-30}{84}) \cdot (\frac{13+8}{16}) = \frac{61}{64} - \frac{19}{84} \cdot \frac{21}{16} = \frac{61}{64} - \frac{19 \cdot 21}{84 \cdot 16} = \frac{61}{64} - \frac{19 \cdot 1}{4 \cdot 16} = \frac{61}{64} - \frac{19}{64} = \frac{42}{64} = \frac{21}{32}$ 2) $(1 - \frac{11}{17}) \cdot (\frac{3}{4} - \frac{5}{12} + \frac{11}{18}) = \frac{6}{17} \cdot (\frac{27 - 15 + 22}{36}) = \frac{6}{17} \cdot \frac{34}{36} = \frac{6 \cdot 34}{17 \cdot 36} = \frac{1 \cdot 2}{1 \cdot 6} = \frac{2}{6} = \frac{1}{3}$ 3) $4 + (\frac{7}{8} + \frac{3}{16}) = 4 + \frac{14 + 3}{16} = 4 + \frac{17}{16} = 4 + 1\frac{1}{16} = 5\frac{1}{16}$ 4) ($\frac{2}{3} + \frac{7}{8}) - (\frac{11}{24} - \frac{5}{12}) = \frac{16 + 21}{24} - \frac{11 - 10}{24} = \frac{37}{24} - \frac{1}{24} = \frac{36}{24} = \frac{3}{2} = 1,5$ 5) $\frac{13}{12} - \frac{12}{13} - \frac{25}{156} = \frac{13 \cdot 13 - 12 \cdot 12}{156} - \frac{25}{156} = \frac{169 - 144}{156} - \frac{25}{156} = \frac{25}{156} - \frac{25}{156} = 0$ **Ответ:** 1) $\frac{21}{32}$; 2) $\frac{1}{3}$; 3) $5\frac{1}{16}$; 4) $1,5$; 5) $0$.