Реши примеры с обыкновенными и смешанными дробями.

1. $(12\frac{3}{8} : 2\frac{1}{16} - 5\frac{5}{21}) \cdot \frac{7}{8} + 3\frac{2}{15} = (\frac{99}{8} \cdot \frac{16}{33} - \frac{110}{21}) \cdot \frac{7}{8} + \frac{47}{15} = (6 - 5\frac{5}{21}) \cdot \frac{7}{8} + 3\frac{2}{15} = \frac{16}{21} \cdot \frac{7}{8} + 3\frac{2}{15} = \frac{2}{3} + 3\frac{2}{15} = \frac{10}{15} + 3\frac{2}{15} = 3\frac{12}{15} = 3\frac{4}{5}$ **Ответ: 3,8** 2. $(6\frac{3}{4} : 4\frac{1}{2} + 2\frac{5}{7}) : 8\frac{3}{7} - \frac{2}{5} = (\frac{27}{4} \cdot \frac{2}{9} + \frac{19}{7}) : \frac{59}{7} - \frac{2}{5} = (\frac{3}{2} + \frac{19}{7}) : \frac{59}{7} - \frac{2}{5} = (\frac{21+38}{14}) \cdot \frac{7}{59} - \frac{2}{5} = \frac{59}{14} \cdot \frac{7}{59} - \frac{2}{5} = \frac{1}{2} - \frac{2}{5} = 0,5 - 0,4 = 0,1$ **Ответ: 0,1** 3. $(1\frac{3}{7} + 4\frac{5}{21} - 5\frac{1}{4}) \cdot 1\frac{5}{7} + 3\frac{1}{7} = (1\frac{9}{21} + 4\frac{5}{21} - 5\frac{1}{4}) \cdot \frac{12}{7} + \frac{22}{7} = (5\frac{14}{21} - 5\frac{1}{4}) \cdot \frac{12}{7} + \frac{22}{7} = (\frac{2}{3} - \frac{1}{4}) \cdot \frac{12}{7} + \frac{22}{7} = \frac{5}{12} \cdot \frac{12}{7} + \frac{22}{7} = \frac{5}{7} + \frac{22}{7} = \frac{27}{7} = 3\frac{6}{7}$ **Ответ: 3\frac{6}{7}** 4. $\frac{1}{3} \cdot (2\frac{2}{15} \cdot 6\frac{1}{4} - 5\frac{1}{3} \cdot 1\frac{1}{8}) = \frac{1}{3} \cdot (\frac{32}{15} \cdot \frac{25}{4} - \frac{16}{3} \cdot \frac{9}{8}) = \frac{1}{3} \cdot (\frac{8 \cdot 5}{3 \cdot 1} - 2 \cdot 3) = \frac{1}{3} \cdot (\frac{40}{3} - 6) = \frac{1}{3} \cdot (13\frac{1}{3} - 6) = \frac{1}{3} \cdot 7\frac{1}{3} = \frac{1}{3} \cdot \frac{22}{3} = \frac{22}{9} = 2\frac{4}{9}$ **Ответ: 2\frac{4}{9}** 5. $1\frac{4}{5} \cdot (12\frac{7}{12} - 9\frac{19}{36}) - \frac{17}{35} \cdot 1\frac{11}{34} = \frac{9}{5} \cdot (12\frac{21}{36} - 9\frac{19}{36}) - \frac{17}{35} \cdot \frac{45}{34} = \frac{9}{5} \cdot 3\frac{2}{36} - \frac{1 \cdot 9}{7 \cdot 2} = \frac{9}{5} \cdot 3\frac{1}{18} - \frac{9}{14} = \frac{9}{5} \cdot \frac{55}{18} - \frac{9}{14} = \frac{11}{2} - \frac{9}{14} = 5,5 - \frac{9}{14} = \frac{77-9}{14} = \frac{68}{14} = 4\frac{12}{14} = 4\frac{6}{7}$ **Ответ: 4\frac{6}{7}** 6. $\frac{11}{12} \cdot 7 + \frac{23}{48} \cdot 4 - 3\frac{1}{3} = \frac{77}{12} + \frac{23}{12} - \frac{10}{3} = \frac{100}{12} - \frac{10}{3} = \frac{25}{3} - \frac{10}{3} = \frac{15}{3} = 5$ **Ответ: 5** 7. (\frac{8}{25} \cdot 15 + \frac{1}{20} \cdot 4) \cdot \frac{3}{8} = (\frac{8 \cdot 3}{5} + \frac{1}{5}) \cdot \frac{3}{8} = (\frac{24}{5} + \frac{1}{5}) \cdot \frac{3}{8} = 5 \cdot \frac{3}{8} = \frac{15}{8} = 1\frac{7}{8}$ **Ответ: 1,875** 8. $(3\frac{1}{4} + 2\frac{1}{6}) : 2\frac{3}{5} - \frac{2}{3} : \frac{4}{9} = (3\frac{3}{12} + 2\frac{2}{12}) : \frac{13}{5} - \frac{2}{3} \cdot \frac{9}{4} = 5\frac{5}{12} \cdot \frac{5}{13} - \frac{3}{2} = \frac{65}{12} \cdot \frac{5}{13} - 1,5 = \frac{25}{12} - 1\frac{6}{12} = 2\frac{1}{12} - 1\frac{6}{12} = \frac{25-18}{12} = \frac{7}{12}$ **Ответ: \frac{7}{12}** 9. $(3\frac{1}{4} + 1\frac{1}{6} : 1\frac{5}{9}) : 2\frac{2}{7} + \frac{2}{3} = (3\frac{1}{4} + \frac{7}{6} \cdot \frac{9}{14}) : \frac{16}{7} + \frac{2}{3} = (3\frac{1}{4} + \frac{3}{4}) \cdot \frac{7}{16} + \frac{2}{3} = 4 \cdot \frac{7}{16} + \frac{2}{3} = \frac{7}{4} + \frac{2}{3} = 1\frac{3}{4} + \frac{2}{3} = \frac{21+8}{12} = \frac{29}{12} = 2\frac{5}{12}$ **Ответ: 2\frac{5}{12}** 10. $(\frac{15}{28} - \frac{11}{36}) \cdot \frac{21}{29} + 6\frac{6}{7} : \frac{16}{21} = (\frac{135-77}{252}) \cdot \frac{21}{29} + \frac{48}{7} \cdot \frac{21}{16} = \frac{58}{252} \cdot \frac{21}{29} + 3 \cdot 3 = \frac{2 \cdot 29}{12 \cdot 21} \cdot \frac{21}{29} + 9 = \frac{2}{12} + 9 = \frac{1}{6} + 9 = 9\frac{1}{6}$ **Ответ: 9\frac{1}{6}**