Выполните действия в выражениях с обыкновенными дробями.

1) $(1\frac{11}{24}+1\frac{13}{36})\cdot 9 = (1\frac{33}{72}+1\frac{26}{72})\cdot 9 = 2\frac{59}{72}\cdot 9 = \frac{203}{72}\cdot 9 = \frac{203}{8} = 25\frac{3}{8}$ 2) $10\cdot (5\frac{7}{10}-3\frac{3}{4}) = 10\cdot (5\frac{14}{20}-3\frac{15}{20}) = 10\cdot (4\frac{34}{20}-3\frac{15}{20}) = 10\cdot 1\frac{19}{20} = 10\cdot \frac{39}{20} = \frac{39}{2} = 19\frac{1}{2}$ 3) $(3\frac{4}{15}+4\frac{5}{6})\cdot (3\frac{17}{18}-2\frac{5}{9}) = (3\frac{8}{30}+4\frac{25}{30})\cdot (3\frac{17}{18}-2\frac{10}{18}) = 7\frac{33}{30}\cdot 1\frac{7}{18} = 8\frac{3}{30}\cdot 1\frac{7}{18} = 8\frac{1}{10}\cdot 1\frac{7}{18} = \frac{81}{10}\cdot \frac{25}{18} = \frac{9\cdot 5}{2\cdot 2} = \frac{45}{4} = 11\frac{1}{4}$ 4) $(8\frac{7}{15}-6\frac{13}{60})\cdot (11\frac{3}{4}-9\frac{7}{8}) = (8\frac{28}{60}-6\frac{13}{60})\cdot (11\frac{6}{8}-9\frac{7}{8}) = 2\frac{15}{60}\cdot 1\frac{7}{8} = 2\frac{1}{4}\cdot 1\frac{7}{8} = \frac{9}{4}\cdot \frac{15}{8} = \frac{135}{32} = 4\frac{7}{32}$ 5) $[(3\frac{2}{5}+1\frac{7}{10})\cdot 1\frac{3}{17}-(2\frac{7}{23}-1\frac{45}{46})\cdot \frac{69}{80}]\cdot \frac{4}{9} = [(3\frac{4}{10}+1\frac{7}{10})\cdot \frac{20}{17}-(2\frac{14}{46}-1\frac{45}{46})\cdot \frac{69}{80}]\cdot \frac{4}{9} = [4\frac{11}{10}\cdot \frac{20}{17}-(1\frac{60}{46}-1\frac{45}{46})\cdot \frac{69}{80}]\cdot \frac{4}{9} = [\frac{51}{10}\cdot \frac{20}{17}-\frac{15}{46}\cdot \frac{69}{80}]\cdot \frac{4}{9} = [3\cdot 2 - \frac{3\cdot 3}{2\cdot 16}]\cdot \frac{4}{9} = [6 - \frac{9}{32}]\cdot \frac{4}{9} = 5\frac{23}{32}\cdot \frac{4}{9} = \frac{183}{32}\cdot \frac{4}{9} = \frac{61}{8\cdot 3} = \frac{61}{24} = 2\frac{13}{24}$ 6) $[(5\frac{7}{12}-3\frac{17}{36})\cdot 1\frac{2}{3}-4\frac{1}{3}\cdot \frac{3}{26}]\cdot (1-\frac{9}{13}) = [(5\frac{21}{36}-3\frac{17}{36})\cdot \frac{5}{3}-\frac{13}{3}\cdot \frac{3}{26}]\cdot \frac{4}{13} = [2\frac{4}{36}\cdot \frac{5}{3}-\frac{1}{2}]\cdot \frac{4}{13} = [2\frac{1}{9}\cdot \frac{5}{3}-\frac{1}{2}]\cdot \frac{4}{13} = [\frac{19}{9}\cdot \frac{5}{3}-\frac{1}{2}]\cdot \frac{4}{13} = [\frac{95}{27}-\frac{1}{2}]\cdot \frac{4}{13} = [\frac{190-27}{54}]\cdot \frac{4}{13} = \frac{163}{54}\cdot \frac{4}{13} = \frac{163\cdot 2}{27\cdot 13} = \frac{326}{351}$