Выполните действия в примерах с обыкновенными дробями.

1. $2\frac{4}{13} \cdot (\frac{3}{8} - \frac{4}{15}) - 11 : 5\frac{1}{2} = \frac{30}{13} \cdot \frac{45 - 32}{120} - 11 : \frac{11}{2} = \frac{30}{13} \cdot \frac{13}{120} - 11 \cdot \frac{2}{11} = \frac{1}{4} - 2 = -1\frac{3}{4}$ 3. $2\frac{1}{2} + \frac{9}{16} \cdot 1\frac{5}{27} - 3\frac{3}{7} : \frac{27}{28} = \frac{5}{2} + \frac{9}{16} \cdot \frac{32}{27} - \frac{24}{7} \cdot \frac{28}{27} = \frac{5}{2} + \frac{2}{3} - \frac{32}{9} = \frac{45 + 12 - 64}{18} = -\frac{7}{18}$ 5. $\frac{3}{4} + 5\frac{1}{4} \cdot (\frac{7}{15} - \frac{10}{21}) - \frac{19}{20} = \frac{3}{4} + \frac{21}{4} \cdot \frac{49 - 50}{105} - \frac{19}{20} = \frac{3}{4} + \frac{21}{4} \cdot (-\frac{1}{105}) - \frac{19}{20} = \frac{3}{4} - \frac{1}{20} - \frac{19}{20} = \frac{3}{4} - 1 = -\frac{1}{4}$ 7. $-\frac{7}{5} + \frac{18}{35} \cdot 1\frac{22}{27} + 4 : 6\frac{2}{13} = -\frac{7}{5} + \frac{18}{35} \cdot \frac{49}{27} + 4 : \frac{80}{13} = -\frac{7}{5} + \frac{2 \cdot 7}{5 \cdot 3} + \frac{4 \cdot 13}{80} = -\frac{7}{5} + \frac{14}{15} + \frac{13}{20} = \frac{-84 + 56 + 39}{60} = \frac{11}{60}$ 9. $5 - (3 - 1\frac{7}{20}) : \frac{9}{25} + \frac{1}{8} = 5 - (1\frac{13}{20}) : \frac{9}{25} + \frac{1}{8} = 5 - \frac{33}{20} \cdot \frac{25}{9} + \frac{1}{8} = 5 - \frac{11 \cdot 5}{4 \cdot 3} + \frac{1}{8} = 5 - \frac{55}{12} + \frac{1}{8} = 5 - 4\frac{7}{12} + \frac{1}{8} = \frac{5}{12} + \frac{1}{8} = \frac{10 + 3}{24} = \frac{13}{24}$ 11. $\frac{29}{4} : 5\frac{4}{5} - \frac{3}{4} \cdot (3 - 1\frac{19}{30}) = \frac{29}{4} : \frac{29}{5} - \frac{3}{4} \cdot 1\frac{11}{30} = \frac{29}{4} \cdot \frac{5}{29} - \frac{3}{4} \cdot \frac{41}{30} = \frac{5}{4} - \frac{41}{40} = \frac{50 - 41}{40} = \frac{9}{40}$ 13. $-1 + (\frac{7}{12} + \frac{5}{6}) : 2\frac{5}{6} - \frac{2}{3} = -1 + (\frac{7 + 10}{12}) : \frac{17}{6} - \frac{2}{3} = -1 + \frac{17}{12} \cdot \frac{6}{17} - \frac{2}{3} = -1 + \frac{1}{2} - \frac{2}{3} = \frac{-6 + 3 - 4}{6} = -\frac{7}{6} = -1\frac{1}{6}$ 15. $\frac{46}{50} : (\frac{7}{20} - \frac{11}{15}) + 3 \cdot 1\frac{11}{15} = \frac{23}{25} : (\frac{21 - 44}{60}) + 3 \cdot \frac{26}{15} = \frac{23}{25} : (-\frac{23}{60}) + \frac{26}{5} = -\frac{23}{25} \cdot \frac{60}{23} + \frac{26}{5} = -\frac{12}{5} + \frac{26}{5} = \frac{14}{5} = 2\frac{4}{5}$ 17. $\frac{11}{14} + \frac{8}{15} : (4 - 2\frac{26}{27}) - 1\frac{1}{10} = \frac{11}{14} + \frac{8}{15} : 1\frac{1}{27} - \frac{11}{10} = \frac{11}{14} + \frac{8}{15} \cdot \frac{27}{28} - \frac{11}{10} = \frac{11}{14} + \frac{2 \cdot 9}{5 \cdot 7} - \frac{11}{10} = \frac{11}{14} + \frac{18}{35} - \frac{11}{10} = \frac{55 + 36 - 77}{70} = \frac{14}{70} = \frac{1}{5} = 0,2$ 19. $\frac{9}{10} + \frac{4}{9} : (2 - 1\frac{11}{21}) - 1\frac{2}{3} = \frac{9}{10} + \frac{4}{9} : \frac{10}{21} - \frac{5}{3} = \frac{9}{10} + \frac{4}{9} \cdot \frac{21}{10} - \frac{5}{3} = \frac{9}{10} + \frac{2 \cdot 7}{3 \cdot 5} - \frac{5}{3} = \frac{9}{10} + \frac{14}{15} - \frac{5}{3} = \frac{27 + 28 - 50}{30} = \frac{5}{30} = \frac{1}{6}$