Выполните действия в выражениях с обыкновенными и десятичными дробями.

1) $\left(-\frac{4}{15} + \frac{7}{12}\right) : \left(-\frac{38}{45}\right) = \left(-\frac{16}{60} + \frac{35}{60}\right) : \left(-\frac{38}{45}\right) = \frac{19}{60} \cdot \left(-\frac{45}{38}\right) = -\frac{1 \cdot 3}{4 \cdot 2} = -\frac{3}{8}$ 2) $\left(-2\frac{11}{15} - 2\frac{7}{20}\right) : \left(-8\frac{17}{36}\right) = \left(-2\frac{44}{60} - 2\frac{21}{60}\right) : \left(-\frac{305}{36}\right) = -4\frac{65}{60} : \left(-\frac{305}{36}\right) = -5\frac{5}{60} : \left(-\frac{305}{36}\right) = -\frac{305}{60} \cdot \left(-\frac{36}{305}\right) = \frac{1 \cdot 36}{60 \cdot 1} = \frac{3}{5}$ 3) $\left(\frac{11}{16} - \left(-\frac{17}{24}\right)\right) : \left(-5\frac{7}{12}\right) = \left(\frac{33}{48} + \frac{34}{48}\right) : \left(-\frac{67}{12}\right) = \frac{67}{48} \cdot \left(-\frac{12}{67}\right) = -\frac{1 \cdot 1}{4 \cdot 1} = -\frac{1}{4}$ 4) $\left(-\frac{11}{18} + \frac{29}{45}\right) : \left(\frac{19}{27} - \frac{35}{54}\right) = \left(-\frac{55}{90} + \frac{58}{90}\right) : \left(\frac{38}{54} - \frac{35}{54}\right) = \frac{3}{90} : \frac{3}{54} = \frac{1}{30} \cdot \frac{54}{3} = \frac{1 \cdot 18}{10 \cdot 3} = \frac{18}{30} = \frac{3}{5}$ 5) $-4\frac{1}{7} + 2\frac{1}{4} \cdot \left(-11\frac{2}{9} - (-5,4) : \frac{9}{35}\right)$ 1. $-5,4 : \frac{9}{35} = -\frac{54}{10} \cdot \frac{35}{9} = -\frac{6 \cdot 7}{2 \cdot 1} = -21$ 2. $-11\frac{2}{9} - (-21) = -11\frac{2}{9} + 21 = 9\frac{7}{9}$ 3. $2\frac{1}{4} \cdot 9\frac{7}{9} = \frac{9}{4} \cdot \frac{88}{9} = \frac{1 \cdot 22}{1 \cdot 1} = 22$ 4. $-4\frac{1}{7} + 22 = 17\frac{6}{7}$ **Ответ: 1) -3/8; 2) 3/5; 3) -1/4; 4) 3/5; 5) 17 6/7.**