164. Решите уравнения:

а) 1) $(x - \frac{1}{4}) + 3\frac{1}{12} = 7\frac{1}{3}$ $x - \frac{1}{4} = 7\frac{4}{12} - 3\frac{1}{12}$ $x - \frac{1}{4} = 4\frac{3}{12}$ $x = 4\frac{1}{4} + \frac{1}{4}$ **Ответ: $x = 4\frac{1}{2}$** 2) $(2\frac{7}{24} - x) + \frac{1}{12} = 2$ $2\frac{7}{24} - x = 2 - \frac{2}{24}$ $2\frac{7}{24} - x = 1\frac{22}{24}$ $x = 2\frac{7}{24} - 1\frac{22}{24} = 1\frac{31}{24} - 1\frac{22}{24}$ **Ответ: $x = \frac{9}{24} = \frac{3}{8}$** б) 1) $6\frac{2}{3} - (x + \frac{1}{4}) = 2\frac{1}{6}$ $x + \frac{1}{4} = 6\frac{4}{6} - 2\frac{1}{6}$ $x + \frac{1}{4} = 4\frac{3}{6}$ $x = 4\frac{1}{2} - \frac{1}{4} = 4\frac{2}{4} - \frac{1}{4}$ **Ответ: $x = 4\frac{1}{4}$** 2) $(2\frac{1}{24} + x) + \frac{1}{12} = 2\frac{1}{6}$ $2\frac{1}{24} + x = 2\frac{4}{24} - \frac{2}{24}$ $2\frac{1}{24} + x = 2\frac{2}{24}$ $x = 2\frac{2}{24} - 2\frac{1}{24}$ **Ответ: $x = \frac{1}{24}$**