Выполните деление; Найдите частное; Найдите значение выражения; Решите уравнение.

Выполните деление: 1) $\frac{3}{4} : \frac{5}{7} = \frac{3}{4} \cdot \frac{7}{5} = \frac{21}{20} = 1\frac{1}{20}$ 2) $\frac{5}{18} : \frac{25}{27} = \frac{5}{18} \cdot \frac{27}{25} = \frac{1 \cdot 3}{2 \cdot 5} = \frac{3}{10}$ 3) $\frac{9}{16} : \frac{3}{64} = \frac{9}{16} \cdot \frac{64}{3} = \frac{3 \cdot 4}{1 \cdot 1} = 12$ 4) $\frac{25}{72} : \frac{45}{63} = \frac{25}{72} \cdot \frac{63}{45} = \frac{5 \cdot 7}{8 \cdot 9} = \frac{35}{72}$ Найдите частное: 1) $8 : \frac{4}{5} = \frac{8}{1} \cdot \frac{5}{4} = 2 \cdot 5 = 10$ 2) $1 : \frac{7}{16} = 1 \cdot \frac{16}{7} = \frac{16}{7} = 2\frac{2}{7}$ 3) $\frac{8}{15} : 24 = \frac{8}{15} \cdot \frac{1}{24} = \frac{1}{15 \cdot 3} = \frac{1}{45}$ 4) $12\frac{1}{2} : 3\frac{3}{4} = \frac{25}{2} : \frac{15}{4} = \frac{25}{2} \cdot \frac{4}{15} = \frac{5 \cdot 2}{1 \cdot 3} = \frac{10}{3} = 3\frac{1}{3}$ 5) $1\frac{3}{5} : 5\frac{1}{3} = \frac{8}{5} : \frac{16}{3} = \frac{8}{5} \cdot \frac{3}{16} = \frac{1 \cdot 3}{5 \cdot 2} = \frac{3}{10}$ 6) $2\frac{5}{8} : \frac{7}{32} = \frac{21}{8} \cdot \frac{32}{7} = 3 \cdot 4 = 12$ Найдите значение выражения: 1) $2\frac{1}{4} : \frac{3}{8} : \frac{1}{2} = \frac{9}{4} \cdot \frac{8}{3} \cdot \frac{2}{1} = 3 \cdot 2 \cdot 2 = 12$ 2) $2\frac{1}{4} : (\frac{3}{8} : \frac{1}{2}) = \frac{9}{4} : (\frac{3}{8} \cdot \frac{2}{1}) = \frac{9}{4} : \frac{3}{4} = \frac{9}{4} \cdot \frac{4}{3} = 3$ 3) $(6\frac{3}{4} - 5\frac{1}{8} : 1\frac{9}{32}) : 2\frac{1}{5} = (\frac{27}{4} - \frac{41}{8} \cdot \frac{32}{41}) : \frac{11}{5} = (\frac{27}{4} - 4) : \frac{11}{5} = (\frac{27-16}{4}) \cdot \frac{5}{11} = \frac{11}{4} \cdot \frac{5}{11} = \frac{5}{4} = 1\frac{1}{4}$ 4) $(3\frac{1}{4} + 2\frac{1}{6}) : 2\frac{3}{5} - \frac{2}{3} : \frac{4}{9} = (3\frac{3}{12} + 2\frac{2}{12}) : \frac{13}{5} - \frac{2}{3} \cdot \frac{9}{4} = 5\frac{5}{12} \cdot \frac{5}{13} - \frac{3}{2} = \frac{65}{12} \cdot \frac{5}{13} - 1\frac{1}{2} = \frac{5 \cdot 5}{12} - \frac{3}{2} = \frac{25}{12} - \frac{18}{12} = \frac{7}{12}$ Решите уравнение: 1) $\frac{6}{5}x = \frac{3}{5} \Rightarrow x = \frac{3}{5} : \frac{6}{5} = \frac{3}{5} \cdot \frac{5}{6} = \frac{1}{2}$ 2) $\frac{4}{7}x = 1 \Rightarrow x = 1 : \frac{4}{7} = \frac{7}{4} = 1\frac{3}{4}$ 3) $\frac{3}{4}x = 12 \Rightarrow x = 12 : \frac{3}{4} = 12 \cdot \frac{4}{3} = 4 \cdot 4 = 16$ 4) $3x = \frac{2}{3} \Rightarrow x = \frac{2}{3} : 3 = \frac{2}{3} \cdot \frac{1}{3} = \frac{2}{9}$ 5) $x : \frac{7}{15} = \frac{15}{28} \Rightarrow x = \frac{15}{28} \cdot \frac{7}{15} = \frac{1}{4}$ 6) $5\frac{1}{4} : x = \frac{7}{8} \Rightarrow x = 5\frac{1}{4} : \frac{7}{8} = \frac{21}{4} \cdot \frac{8}{7} = 3 \cdot 2 = 6$