Реши неравенство 18-8(x-2) < 10-4x

Решаю неравенства по порядку: 690. $18 - 8(x - 2) < 10 - 4x$ $18 - 8x + 16 < 10 - 4x$ $34 - 8x < 10 - 4x$ $-8x + 4x < 10 - 34$ $-4x < -24$ $x > 6$ 691. $10x - 3(4 - 2x) > 16 + 20x$ $10x - 12 + 6x > 16 + 20x$ $16x - 12 > 16 + 20x$ $16x - 20x > 16 + 12$ $-4x > 28$ $x < -7$ 692. $3 - 5(2x + 4) \ge 7 - 2x$ $3 - 10x - 20 \ge 7 - 2x$ $-10x - 17 \ge 7 - 2x$ $-10x + 2x \ge 7 + 17$ $-8x \ge 24$ $x \le -3$ 693. $19 - 7x < 20 - 3(x - 5)$ $19 - 7x < 20 - 3x + 15$ $19 - 7x < 35 - 3x$ $-7x + 3x < 35 - 19$ $-4x < 16$ $x > -4$ 694. $3x - 10(2 + x) < x + 4$ $3x - 20 - 10x < x + 4$ $-7x - 20 < x + 4$ $-7x - x < 4 + 20$ $-8x < 24$ $x > -3$ 695. $2(x - 1) > 5x - 4(2x + 1)$ $2x - 2 > 5x - 8x - 4$ $2x - 2 > -3x - 4$ $2x + 3x > -4 + 2$ $5x > -2$ $x > -\frac{2}{5}$ 696. $9x - 2(2x - 3) < 3(x + 1)$ $9x - 4x + 6 < 3x + 3$ $5x + 6 < 3x + 3$ $5x - 3x < 3 - 6$ $2x < -3$ $x < -\frac{3}{2}$ 697. $2(1 - x) \ge 5x - (3x + 2)$ $2 - 2x \ge 5x - 3x - 2$ $2 - 2x \ge 2x - 2$ $-2x - 2x \ge -2 - 2$ $-4x \ge -4$ $x \le 1$ 698. $3x - (2x - 7) \le 3(1 + x)$ $3x - 2x + 7 \le 3 + 3x$ $x + 7 \le 3 + 3x$ $x - 3x \le 3 - 7$ $-2x \le -4$ $x \ge 2$