Помоги мне найти значение выражения: 1-1 4/9

85. Найди значения выражений. а) $1 \frac{4}{9} = \frac{9}{9} + \frac{4}{9} = \frac{13}{9}$ б) $1 + 1 \frac{5}{6} = 1 + \frac{11}{6} = \frac{6}{6} + \frac{11}{6} = \frac{17}{6}$ в) $7 - \frac{3}{8} = \frac{56}{8} - \frac{3}{8} = \frac{53}{8}$ г) $4 - 3 \frac{3}{4} = 4 - \frac{15}{4} = \frac{16}{4} - \frac{15}{4} = \frac{1}{4}$ 86. Выполни действия. а) $4 \frac{5}{6} + 2 \frac{3}{8} = \frac{29}{6} + \frac{19}{8} = \frac{116}{24} + \frac{57}{24} = \frac{173}{24}$ б) $7 \frac{5}{18} - 1 \frac{7}{12} = \frac{131}{18} - \frac{19}{12} = \frac{262}{36} - \frac{57}{36} = \frac{205}{36}$ в) $3 \frac{4}{9} + 2 \frac{2}{7} = \frac{31}{9} + \frac{16}{7} = \frac{217}{63} + \frac{144}{63} = \frac{361}{63}$ г) $5 \frac{3}{14} - 1 \frac{1}{21} = \frac{73}{14} - \frac{22}{21} = \frac{219}{42} - \frac{44}{42} = \frac{175}{42}$ 135. Выполни действия: а) $(1 \frac{3}{5} + 2 \frac{1}{10}) : 1 \frac{9}{10} + (1 \frac{7}{10} - \frac{4}{5}) : \frac{3}{7} = (\frac{8}{5} + \frac{21}{10}) : \frac{19}{10} + (\frac{17}{10} - \frac{8}{10}) : \frac{3}{7} = \frac{37}{10} \cdot \frac{10}{19} + \frac{9}{10} : \frac{3}{7} = \frac{37}{19} + \frac{9}{10} \cdot \frac{7}{3} = \frac{37}{19} + \frac{3}{10} \cdot \frac{7}{1} = \frac{37}{19} + \frac{21}{10} = \frac{370}{190} + \frac{399}{190} = \frac{769}{190}$ б) $6 \frac{3}{8} \cdot 1 \frac{1}{17} - 2 \frac{3}{4} : 1 \frac{1}{2} + \frac{2}{5} = \frac{51}{8} \cdot \frac{18}{17} - \frac{11}{4} : \frac{3}{2} + \frac{2}{5} = \frac{3}{8} \cdot \frac{18}{1} - \frac{11}{4} \cdot \frac{2}{3} + \frac{2}{5} = \frac{54}{8} - \frac{11}{6} + \frac{2}{5} = \frac{27}{4} - \frac{11}{6} + \frac{2}{5} = \frac{405}{60} - \frac{110}{60} + \frac{24}{60} = \frac{319}{60}$