Помоги мне найти значение выражения в номере 105 (а, б, в, г, д, е).

- a) $3 \frac{3}{7} + 1 \frac{3}{14} \cdot (8 \frac{3}{5} - 1 \frac{3}{5}) = \frac{24}{7} + \frac{17}{14} \cdot (\frac{43}{5} - \frac{8}{5}) = \frac{24}{7} + \frac{17}{14} \cdot \frac{35}{5} = \frac{24}{7} + \frac{17}{2} \cdot \frac{1}{1} = \frac{24}{7} + \frac{17}{2} = \frac{48}{14} + \frac{119}{14} = \frac{167}{14} = 11 \frac{13}{14}$ - б) $2 \frac{5}{9} \cdot 2 \frac{1}{4} - 6 \frac{2}{3} : \frac{9}{8} = \frac{23}{9} \cdot \frac{9}{4} - \frac{20}{3} : \frac{9}{8} = \frac{23}{4} - \frac{20}{3} \cdot \frac{8}{9} = \frac{23}{4} - \frac{160}{27} = \frac{621}{108} - \frac{640}{108} = -\frac{19}{108}$ - в) $(6 \frac{2}{5} - 2 \frac{11}{12} - 16) \cdot 2 \frac{1}{4} = (\frac{32}{5} - \frac{35}{12} - 16) \cdot \frac{9}{4} = (\frac{32 \cdot 12}{5 \cdot 12} - \frac{35 \cdot 5}{12 \cdot 5} - \frac{16 \cdot 60}{60}) \cdot \frac{9}{4} = (\frac{384}{60} - \frac{175}{60} - \frac{960}{60}) \cdot \frac{9}{4} = (\frac{384 - 175 - 960}{60}) \cdot \frac{9}{4} = \frac{-71}{60} \cdot \frac{9}{4} = -\frac{213}{80} = -2 \frac{53}{80}$ - г) $(\frac{1}{2})^3 \cdot (3 \frac{1}{3} - 2 \frac{8}{9})^2 = \frac{1}{8} \cdot (\frac{10}{3} - \frac{26}{9})^2 = \frac{1}{8} \cdot (\frac{30}{9} - \frac{26}{9})^2 = \frac{1}{8} \cdot (\frac{4}{9})^2 = \frac{1}{8} \cdot \frac{16}{81} = \frac{2}{81}$ - д) $(3 \frac{2}{3} - 2 \frac{1}{2}) \cdot 2 \frac{1}{7} = (\frac{11}{3} - \frac{5}{2}) \cdot \frac{15}{7} = (\frac{22}{6} - \frac{15}{6}) \cdot \frac{15}{7} = \frac{7}{6} \cdot \frac{15}{7} = \frac{15}{6} = \frac{5}{2} = 2 \frac{1}{2}$ - е) $12 \cdot (\frac{11}{12} - \frac{9}{10}) \cdot (3 - 1 \frac{1}{3}) = 12 \cdot (\frac{55}{60} - \frac{54}{60}) \cdot (\frac{9}{3} - \frac{4}{3}) = 12 \cdot \frac{1}{60} \cdot \frac{5}{3} = \frac{1}{5} \cdot \frac{5}{3} = \frac{1}{3}$ **Ответы:** - a) $11 \frac{13}{14}$ - б) $-\frac{19}{108}$ - в) $-2 \frac{53}{80}$ - г) $\frac{2}{81}$ - д) $2 \frac{1}{2}$ - е) $\frac{1}{3}$