Реши примеры с обыкновенными дробями: 4 1/7 * 14 - 1 1/4 * 1 1/6 - 1 2/9 * 2 5/8

1. $4 \frac{1}{7} \cdot 14 - 1 \frac{1}{4} \cdot 1 \frac{1}{6} - 1 \frac{2}{9} \cdot 2 \frac{5}{8} = \frac{29}{7} \cdot 14 - \frac{5}{4} \cdot \frac{7}{6} - \frac{11}{9} \cdot \frac{21}{8} = 58 - \frac{35}{24} - \frac{77}{24} = 58 - \frac{112}{24} = 58 - \frac{14}{3} = \frac{174 - 14}{3} = \frac{160}{3} = 53 \frac{1}{3}$ 2. $1 \frac{31}{32} \cdot 3 \frac{1}{5} + (8 \frac{5}{9} \cdot \frac{6}{35} + 3 \frac{8}{15}) \cdot \frac{7}{50} = \frac{63}{32} \cdot \frac{16}{5} + (\frac{77}{9} \cdot \frac{6}{35} + \frac{53}{15}) \cdot \frac{7}{50} = \frac{63}{10} + (\frac{22}{15} + \frac{53}{15}) \cdot \frac{7}{50} = \frac{63}{10} + \frac{75}{15} \cdot \frac{7}{50} = \frac{63}{10} + 5 \cdot \frac{7}{50} = \frac{63}{10} + \frac{7}{10} = \frac{70}{10} = 7$ 3. $1 \frac{5}{12} \cdot 2 + 4 \cdot 1 \frac{1}{18} + 1 \frac{1}{9} \cdot 1 \frac{1}{4} = \frac{17}{12} \cdot 2 + 4 \cdot \frac{19}{18} + \frac{10}{9} \cdot \frac{5}{4} = \frac{17}{6} + \frac{38}{9} + \frac{25}{18} = \frac{51 + 76 + 25}{18} = \frac{152}{18} = \frac{76}{9} = 8 \frac{4}{9}$ 4. $2 \frac{1}{10} \cdot 4 \frac{1}{6} + 5 \cdot \frac{3}{8} - \frac{9}{20} \cdot 6 = \frac{21}{10} \cdot \frac{25}{6} + \frac{15}{8} - \frac{27}{10} = \frac{35}{4} + \frac{15}{8} - \frac{27}{10} = \frac{350 + 75 - 108}{40} = \frac{317}{40} = 7 \frac{37}{40}$ 5. $3 \cdot 2 \frac{7}{15} - 5 \frac{1}{2} \cdot \frac{7}{9} + 1 \frac{7}{48} \cdot 2 \frac{2}{11} - \frac{2}{5} \cdot 6 \frac{5}{9} = 3 \cdot \frac{37}{15} - \frac{11}{2} \cdot \frac{7}{9} + \frac{55}{48} \cdot \frac{24}{11} - \frac{2}{5} \cdot \frac{59}{9} = \frac{37}{5} - \frac{77}{18} + \frac{5}{2} - \frac{118}{45} = \frac{37 \cdot 18 - 77 \cdot 5 + 5 \cdot 45 - 118 \cdot 2}{90} = \frac{666 - 385 + 225 - 236}{90} = \frac{270}{90} = 3$ 6. $(6 \frac{7}{12} - 3 \frac{17}{36}) \cdot \frac{1}{2} + 4 \frac{1}{3} : \frac{13}{20} = (\frac{79}{12} - \frac{125}{36}) \cdot \frac{1}{2} + \frac{13}{3} : \frac{13}{20} = (\frac{237 - 125}{36}) \cdot \frac{1}{2} + \frac{13}{3} \cdot \frac{20}{13} = \frac{112}{36} \cdot \frac{1}{2} + \frac{20}{3} = \frac{28}{18} + \frac{20}{3} = \frac{14}{9} + \frac{60}{9} = \frac{74}{9} = 8 \frac{2}{9}$ 7. $(1 \frac{11}{24} + \frac{13}{36}) \cdot 1 \frac{11}{25} - \frac{8}{15} \cdot \frac{9}{16} = (\frac{35}{24} + \frac{13}{36}) \cdot \frac{36}{25} - \frac{3}{10} = (\frac{105 + 26}{72}) \cdot \frac{36}{25} - \frac{3}{10} = \frac{131}{72} \cdot \frac{36}{25} - \frac{3}{10} = \frac{131}{50} - \frac{3}{10} = \frac{131 - 15}{50} = \frac{116}{50} = \frac{58}{25} = 2 \frac{8}{25}$ 8. $2 \frac{1}{2} \cdot 48 - 3 \frac{2}{3} : \frac{1}{18} + 5 \frac{5}{12} : \frac{7}{36} = \frac{5}{2} \cdot 48 - \frac{11}{3} : \frac{1}{18} + \frac{65}{12} : \frac{7}{36} = 5 \cdot 24 - \frac{11}{3} \cdot 18 + \frac{65}{12} \cdot \frac{36}{7} = 120 - 11 \cdot 6 + \frac{65 \cdot 3}{7} = 120 - 66 + \frac{195}{7} = 54 + \frac{195}{7} = \frac{378 + 195}{7} = \frac{573}{7} = 81 \frac{6}{7}$