Вопрос:

Ты просишь выполнить сложение обыкновенных дробей в вариантах 1, 2, 3 и 4.

Фотография

Ответ ассистента

Привет! Давай помогу тебе сложить дроби. Вот ответы для каждого варианта: **Вариант 1** 1) $\frac{2}{5} + \frac{1}{10} = \frac{4}{10} + \frac{1}{10} = \frac{5}{10} = \frac{1}{2}$ 2) $\frac{5}{6} + \frac{2}{3} = \frac{5}{6} + \frac{4}{6} = \frac{9}{6} = \frac{3}{2} = 1\frac{1}{2}$ 3) $\frac{3}{4} + \frac{7}{12} = \frac{9}{12} + \frac{7}{12} = \frac{16}{12} = \frac{4}{3} = 1\frac{1}{3}$ 4) $\frac{2}{15} + \frac{4}{5} = \frac{2}{15} + \frac{12}{15} = \frac{14}{15}$ 5) $\frac{5}{7} + \frac{3}{14} = \frac{10}{14} + \frac{3}{14} = \frac{13}{14}$ 6) $\frac{3}{11} + \frac{6}{55} = \frac{15}{55} + \frac{6}{55} = \frac{21}{55}$ 7) $\frac{1}{6} + \frac{1}{9} = \frac{3}{18} + \frac{2}{18} = \frac{5}{18}$ 8) $\frac{1}{10} + \frac{1}{15} = \frac{3}{30} + \frac{2}{30} = \frac{5}{30} = \frac{1}{6}$ 9) $\frac{2}{8} + \frac{1}{12} = \frac{6}{24} + \frac{2}{24} = \frac{8}{24} = \frac{1}{3}$ 10) $\frac{1}{9} + \frac{1}{2} = \frac{2}{18} + \frac{9}{18} = \frac{11}{18}$ **Вариант 2** 1) $\frac{1}{4} + \frac{1}{12} = \frac{3}{12} + \frac{1}{12} = \frac{4}{12} = \frac{1}{3}$ 2) $\frac{1}{6} + \frac{2}{3} = \frac{1}{6} + \frac{4}{6} = \frac{5}{6}$ 3) $\frac{7}{8} + \frac{3}{4} = \frac{7}{8} + \frac{6}{8} = \frac{13}{8} = 1\frac{5}{8}$ 4) $\frac{4}{7} + \frac{2}{21} = \frac{12}{21} + \frac{2}{21} = \frac{14}{21} = \frac{2}{3}$ 5) $\frac{9}{12} + \frac{3}{4} = \frac{9}{12} + \frac{9}{12} = \frac{18}{12} = \frac{3}{2} = 1\frac{1}{2}$ 6) $\frac{8}{9} + \frac{1}{3} = \frac{8}{9} + \frac{3}{9} = \frac{11}{9} = 1\frac{2}{9}$ 7) $\frac{4}{5} + \frac{7}{15} = \frac{12}{15} + \frac{7}{15} = \frac{19}{15} = 1\frac{4}{15}$ 8) $\frac{2}{21} + \frac{5}{14} = \frac{4}{42} + \frac{15}{42} = \frac{19}{42}$ 9) $\frac{3}{18} + \frac{5}{27} = \frac{9}{54} + \frac{10}{54} = \frac{19}{54}$ 10) $\frac{3}{15} + \frac{7}{20} = \frac{12}{60} + \frac{21}{60} = \frac{33}{60} = \frac{11}{20}$ **Вариант 3** 1) $\frac{3}{8} + \frac{7}{16} = \frac{6}{16} + \frac{7}{16} = \frac{13}{16}$ 2) $\frac{5}{6} + \frac{11}{18} = \frac{15}{18} + \frac{11}{18} = \frac{26}{18} = \frac{13}{9} = 1\frac{4}{9}$ 3) $\frac{7}{11} + \frac{5}{33} = \frac{21}{33} + \frac{5}{33} = \frac{26}{33}$ 4) $\frac{8}{9} + \frac{5}{18} = \frac{16}{18} + \frac{5}{18} = \frac{21}{18} = \frac{7}{6} = 1\frac{1}{6}$ 5) $\frac{3}{5} + \frac{2}{15} = \frac{9}{15} + \frac{2}{15} = \frac{11}{15}$ 6) $\frac{8}{17} + \frac{1}{34} = \frac{16}{34} + \frac{1}{34} = \frac{17}{34} = \frac{1}{2}$ 7) $\frac{1}{4} + \frac{1}{6} = \frac{3}{12} + \frac{2}{12} = \frac{5}{12}$ 8) $\frac{5}{8} + \frac{1}{10} = \frac{25}{40} + \frac{4}{40} = \frac{29}{40}$ 9) $\frac{7}{9} + \frac{1}{6} = \frac{14}{18} + \frac{3}{18} = \frac{17}{18}$ 10) $\frac{2}{21} + \frac{3}{14} = \frac{4}{42} + \frac{9}{42} = \frac{13}{42}$ **Вариант 4** 1) $\frac{1}{2} + \frac{3}{4} = \frac{2}{4} + \frac{3}{4} = \frac{5}{4} = 1\frac{1}{4}$ 2) $\frac{6}{7} + \frac{5}{14} = \frac{12}{14} + \frac{5}{14} = \frac{17}{14} = 1\frac{3}{14}$ 3) $\frac{2}{3} + \frac{7}{12} = \frac{8}{12} + \frac{7}{12} = \frac{15}{12} = \frac{5}{4} = 1\frac{1}{4}$ 4) $\frac{4}{5} + \frac{3}{20} = \frac{16}{20} + \frac{3}{20} = \frac{19}{20}$ 5) $\frac{4}{9} + \frac{7}{18} = \frac{8}{18} + \frac{7}{18} = \frac{15}{18} = \frac{5}{6}$ 6) $\frac{9}{10} + \frac{4}{15} = \frac{27}{30} + \frac{8}{30} = \frac{35}{30} = \frac{7}{6} = 1\frac{1}{6}$ 7) $\frac{5}{6} + \frac{3}{14} = \frac{35}{42} + \frac{9}{42} = \frac{44}{42} = \frac{22}{21} = 1\frac{1}{21}$ 8) $\frac{5}{12} + \frac{1}{18} = \frac{15}{36} + \frac{2}{36} = \frac{17}{36}$ 9) $\frac{1}{9} + \frac{3}{12} = \frac{4}{36} + \frac{9}{36} = \frac{13}{36}$ 10) $\frac{3}{4} + \frac{1}{6} = \frac{9}{12} + \frac{2}{12} = \frac{11}{12}$

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