Помоги вычислить выражения в задании 6 а)

- а) $6\frac{1}{8} - 8 = \frac{49}{8} - 8 = \frac{49}{8} - \frac{64}{8} = -\frac{15}{8} = -1\frac{7}{8}$ - б) $-2\frac{7}{8} + 4\frac{5}{8} = -\frac{23}{8} + \frac{37}{8} = \frac{14}{8} = \frac{7}{4} = 1\frac{3}{4}$ - в) $5\frac{3}{8} - 6\frac{1}{4} = \frac{43}{8} - \frac{25}{4} = \frac{43}{8} - \frac{50}{8} = -\frac{7}{8}$ - г) $\frac{8}{9} : (-\frac{8}{16}) = \frac{8}{9} : (-\frac{1}{2}) = \frac{8}{9} * (-2) = -\frac{16}{9} = -1\frac{7}{9}$ - д) $12\frac{5}{6} \cdot (-6) = \frac{77}{6} \cdot (-6) = -77$ - ж) $\frac{4}{7} \cdot (-49) = -\frac{4 \cdot 49}{7} = -4 \cdot 7 = -28$ - з) $-16 : (-\frac{4}{9}) = -16 \cdot (-\frac{9}{4}) = \frac{16 \cdot 9}{4} = 4 \cdot 9 = 36$ - и) $-3\frac{1}{2} \cdot (-1\frac{2}{7}) = -\frac{7}{2} \cdot (-\frac{9}{7}) = \frac{7 \cdot 9}{2 \cdot 7} = \frac{9}{2} = 4\frac{1}{2}$