Ты просишь упростить выражения в задачах на повторение.

Конечно, сейчас помогу упростить выражения! 1. a) $\frac{1}{x^2} + \frac{x-2}{x} = \frac{1}{x^2} + \frac{x(x-2)}{x^2} = \frac{1 + x^2 - 2x}{x^2} = \frac{x^2 - 2x + 1}{x^2} = \frac{(x-1)^2}{x^2}$ б) $\frac{3}{x+y} + \frac{5}{x-y} = \frac{3(x-y) + 5(x+y)}{(x+y)(x-y)} = \frac{3x - 3y + 5x + 5y}{x^2 - y^2} = \frac{8x + 2y}{x^2 - y^2}$ в) $\frac{1-5d^2}{d^6} - \frac{d-5}{d^4} + \frac{1}{d^2} = \frac{1-5d^2 - d^2(d-5) + d^4}{d^6} = \frac{1 - 5d^2 - d^3 + 5d^2 + d^4}{d^6} = \frac{d^4 - d^3 + 1}{d^6}$ г) $\frac{5c}{6c-6} - \frac{4c}{3c+3} + \frac{c^2}{2c^2-2} = \frac{5c}{6(c-1)} - \frac{4c}{3(c+1)} + \frac{c^2}{2(c^2-1)} = \frac{5c}{6(c-1)} - \frac{4c}{3(c+1)} + \frac{c^2}{2(c-1)(c+1)} = \frac{5c(c+1) - 4c \cdot 2(c-1) + c^2 \cdot 3}{6(c-1)(c+1)} = \frac{5c^2 + 5c - 8c^2 + 8c + 3c^2}{6(c-1)(c+1)} = \frac{13c}{6(c-1)(c+1)} = \frac{13c}{6(c^2-1)}$ 2. a) $\frac{3c+2}{c^2-4c+4} - \frac{5}{c-2} = \frac{3c+2}{(c-2)^2} - \frac{5}{c-2} = \frac{3c+2 - 5(c-2)}{(c-2)^2} = \frac{3c+2 - 5c + 10}{(c-2)^2} = \frac{-2c + 12}{(c-2)^2}$ б) $\frac{2mn}{m^3+n^3} + \frac{2m}{m^2-n^2} - \frac{1}{m-n} = \frac{2mn}{(m+n)(m^2-mn+n^2)} + \frac{2m}{(m-n)(m+n)} - \frac{1}{m-n} = \frac{2mn(m-n) + 2m(m^2-mn+n^2) - (m+n)(m^2-mn+n^2)}{(m+n)(m-n)(m^2-mn+n^2)} = \frac{2m^2n - 2mn^2 + 2m^3 - 2m^2n + 2mn^2 - (m^3 + n^3)}{(m+n)(m-n)(m^2-mn+n^2)} = \frac{2m^3 - m^3 - n^3}{(m+n)(m-n)(m^2-mn+n^2)} = \frac{m^3 - n^3}{(m+n)(m-n)(m^2-mn+n^2)} = \frac{(m-n)(m^2+mn+n^2)}{(m+n)(m-n)(m^2-mn+n^2)} = \frac{m^2+mn+n^2}{(m+n)(m^2-mn+n^2)}$