Реши уравнения: a) x + 2 12/14 = 5 5/7

Решаем уравнения: а) $x + 2\frac{12}{14} = 5\frac{5}{7}$ $x = 5\frac{5}{7} - 2\frac{12}{14}$ $x = 5\frac{10}{14} - 2\frac{12}{14}$ $x = 4\frac{24}{14} - 2\frac{12}{14}$ $x = 2\frac{12}{14} = 2\frac{6}{7}$ б) $\frac{4}{5} + y = \frac{23}{25}$ $y = \frac{23}{25} - \frac{4}{5}$ $y = \frac{23}{25} - \frac{20}{25}$ $y = \frac{3}{25}$ в) $A - 4\frac{2}{7} = 2\frac{3}{4}$ $A = 2\frac{3}{4} + 4\frac{2}{7}$ $A = 2\frac{21}{28} + 4\frac{8}{28}$ $A = 6\frac{29}{28} = 7\frac{1}{28}$ г) $\frac{25}{36} - K = \frac{2}{6}$ $\frac{25}{36} - K = \frac{12}{36}$ $K = \frac{25}{36} - \frac{12}{36}$ $K = \frac{13}{36}$ д) $\frac{6}{7} \cdot C = \frac{18}{21}$ $\frac{6}{7} \cdot C = \frac{6}{7}$ $C = \frac{6}{7} : \frac{6}{7}$ $C = 1$ е) $E \cdot 2\frac{2}{9} = 3\frac{3}{9}$ $E \cdot 2\frac{2}{9} = 3\frac{1}{3}$ $E \cdot \frac{20}{9} = \frac{10}{3}$ $E = \frac{10}{3} : \frac{20}{9}$ $E = \frac{10}{3} \cdot \frac{9}{20} = \frac{1}{1} \cdot \frac{3}{2} = \frac{3}{2} = 1\frac{1}{2}$ ж) $M : 3\frac{1}{7} = 2\frac{4}{33}$ $M : \frac{22}{7} = \frac{70}{33}$ $M = \frac{70}{33} \cdot \frac{22}{7} = \frac{10}{3} \cdot \frac{2}{1} = \frac{20}{3} = 6\frac{2}{3}$ з) $1\frac{11}{25} : B = \frac{5}{6}$ $\frac{36}{25} : B = \frac{5}{6}$ $B = \frac{36}{25} : \frac{5}{6}$ $B = \frac{36}{25} \cdot \frac{6}{5} = \frac{216}{125} = 1\frac{91}{125}$ и) $(\frac{8}{15} + \frac{2}{9}X) : \frac{3}{5} = 2$ $\frac{8}{15} + \frac{2}{9}X = 2 \cdot \frac{3}{5}$ $\frac{8}{15} + \frac{2}{9}X = \frac{6}{5}$ $\frac{2}{9}X = \frac{6}{5} - \frac{8}{15}$ $\frac{2}{9}X = \frac{18}{15} - \frac{8}{15}$ $\frac{2}{9}X = \frac{10}{15} = \frac{2}{3}$ X = $\frac{2}{3} : \frac{2}{9}$ X = $\frac{2}{3} \cdot \frac{9}{2} = 3$ к) $2\frac{1}{15} - \frac{3}{4}y = \frac{59}{60}$ $\frac{31}{15} - \frac{3}{4}y = \frac{59}{60}$ $\frac{3}{4}y = \frac{31}{15} - \frac{59}{60}$ $\frac{3}{4}y = \frac{124}{60} - \frac{59}{60}$ $\frac{3}{4}y = \frac{65}{60} = \frac{13}{12}$ y = $\frac{13}{12} : \frac{3}{4}$ y = $\frac{13}{12} \cdot \frac{4}{3} = \frac{13}{3} \cdot \frac{1}{3} = \frac{13}{9} = 1\frac{4}{9}$ л) $6 \cdot (-\frac{5}{6}C - 1\frac{1}{3}) = 5$ $6 \cdot (-\frac{5}{6}C - \frac{4}{3}) = 5$ $-\frac{5}{6}C - \frac{4}{3} = \frac{5}{6}$ $-\frac{5}{6}C = \frac{5}{6} + \frac{4}{3}$ $-\frac{5}{6}C = \frac{5}{6} + \frac{8}{6}$ $-\frac{5}{6}C = \frac{13}{6}$ C = $\frac{13}{6} : -\frac{5}{6}$ C = $\frac{13}{6} \cdot -\frac{6}{5} = -\frac{13}{5} = -2\frac{3}{5}$