Помоги сократить дроби: 7ab/21bc

Конечно, давай сократим дроби! г) $\frac{7ab}{21bc} = \frac{7}{21} \cdot \frac{a}{c} \cdot \frac{b}{b} = \frac{1}{3} \cdot \frac{a}{c} = \frac{a}{3c}$ д) $\frac{-2xy}{5x^2y} = -\frac{2}{5} \cdot \frac{x}{x^2} \cdot \frac{y}{y} = -\frac{2}{5} \cdot \frac{1}{x} = -\frac{2}{5x}$ е) $\frac{8x^2y^2}{24xy} = \frac{8}{24} \cdot \frac{x^2}{x} \cdot \frac{y^2}{y} = \frac{1}{3} \cdot x \cdot y = \frac{xy}{3}$ г) $\frac{-6p^2q}{-2q^3} = \frac{-6}{-2} \cdot \frac{p^2}{1} \cdot \frac{q}{q^3} = 3 \cdot p^2 \cdot \frac{1}{q^2} = \frac{3p^2}{q^2}$ д) $\frac{24a^2c^2}{36ac} = \frac{24}{36} \cdot \frac{a^2}{a} \cdot \frac{c^2}{c} = \frac{2}{3} \cdot a \cdot c = \frac{2ac}{3}$ е) $\frac{63x^2y^3}{42x^6y^4} = \frac{63}{42} \cdot \frac{x^2}{x^6} \cdot \frac{y^3}{y^4} = \frac{3}{2} \cdot \frac{1}{x^4} \cdot \frac{1}{y} = \frac{3}{2x^4y}$ г) $36m^2n : (18mn) = \frac{36m^2n}{18mn} = \frac{36}{18} \cdot \frac{m^2}{m} \cdot \frac{n}{n} = 2 \cdot m \cdot 1 = 2m$ д) $-32b^5c : (12b^4c^2) = \frac{-32b^5c}{12b^4c^2} = -\frac{32}{12} \cdot \frac{b^5}{b^4} \cdot \frac{c}{c^2} = -\frac{8}{3} \cdot b \cdot \frac{1}{c} = -\frac{8b}{3c}$ е) $-6ax : (-18ax) = \frac{-6ax}{-18ax} = \frac{-6}{-18} \cdot \frac{a}{a} \cdot \frac{x}{x} = \frac{1}{3} \cdot 1 \cdot 1 = \frac{1}{3}$ Надеюсь, теперь тебе стало понятнее!