Помоги мне вычислить примеры: а) 6 1/3 - 8 2/7

Конечно, давай решим эти примеры вместе! а) $6\frac{1}{3} - 8\frac{2}{7} = \frac{19}{3} - \frac{58}{7} = \frac{19 \cdot 7 - 58 \cdot 3}{21} = \frac{133 - 174}{21} = \frac{-41}{21} = -1\frac{20}{21}$ б) $-2\frac{2}{7} + 4\frac{1}{5} = -\frac{16}{7} + \frac{21}{5} = \frac{-16 \cdot 5 + 21 \cdot 7}{35} = \frac{-80 + 147}{35} = \frac{67}{35} = 1\frac{32}{35}$ в) $5\frac{1}{3} - 6\frac{1}{4} = \frac{16}{3} - \frac{25}{4} = \frac{16 \cdot 4 - 25 \cdot 3}{12} = \frac{64 - 75}{12} = \frac{-11}{12}$ г) $3\frac{5}{8} : (-\frac{9}{16}) = \frac{29}{8} : (-\frac{9}{16}) = \frac{29}{8} \cdot (-\frac{16}{9}) = -\frac{29 \cdot 16}{8 \cdot 9} = -\frac{29 \cdot 2}{9} = -\frac{58}{9} = -6\frac{4}{9}$ д) $\frac{5}{12} \cdot (-6) = \frac{5 \cdot (-6)}{12} = \frac{-30}{12} = -\frac{5}{2} = -2.5$ е) $-3\frac{2}{9} \cdot 3 = -\frac{29}{9} \cdot 3 = -\frac{29 \cdot 3}{9} = -\frac{29}{3} = -9\frac{2}{3}$ ж) $4\frac{3}{7} \cdot (-49) = \frac{31}{7} \cdot (-49) = \frac{31 \cdot (-49)}{7} = 31 \cdot (-7) = -217$ з) $-16 : (-\frac{4}{9}) = -16 \cdot (-\frac{9}{4}) = \frac{-16 \cdot (-9)}{4} = \frac{16 \cdot 9}{4} = 4 \cdot 9 = 36$ и) $-3\frac{1}{2} \cdot (-1\frac{3}{5}) = -\frac{7}{2} \cdot (-\frac{8}{5}) = \frac{7 \cdot 8}{2 \cdot 5} = \frac{7 \cdot 4}{5} = \frac{28}{5} = 5\frac{3}{5}$